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Serhud [2]
3 years ago
6

Consider the chemical reaction below.

Chemistry
1 answer:
Bingel [31]3 years ago
8 0

I think it is A but idk for sure HOPE THIS HELPES :)

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You have two solid substances that look the same. What measurements would you take and which tests would you preform to determin
ASHA 777 [7]

Answer:

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5 0
3 years ago
The following data is collected after eluting a TLC plate containing three sample spots (A, B, and C): distance traveled by comp
RideAnS [48]

Answer:

Rf = 0.26

Explanation:

The Rf value is calculated by dividing the distance traveled by a compound, by the distance traveled by the solvent front. In other words, the length of the TLC plate is not relevant in calculating a Rf value.

  • Distance traveled by compound C = 18 mm
  • Distance traveled by the solvent front = 70 mm
  • Rf = 18/70 = 0.26
3 0
3 years ago
You perform recrystallization of 1 g of impure acetanilide from water. The solubility of pure acetanilide in hot water is 55g/L.
likoan [24]

Answer:

38.32 mL is minimal volume of hot water that is needed to dissolve 2.1 g of pure acetanilide.

Explanation:

Mass of acetanilide to be dissolved in hot water = 2.1 g

Mass of hot water to be used = m

Solubility of acetanilide = 55 g/L

This means that 55 grams of acetanilide dissolves in 1 L of hot water.

Then 1 grams of acetanilide will dissolve in :

\frac{1}{55}\times 2.1 L=0.0382 L

0.0382 L = 0.0382 × 1000 mL =38.2 mL

1 L = 1000 mL

38.32 mL is minimal volume of hot water that is needed to dissolve 2.1 g of pure acetanilide.

8 0
3 years ago
Identify the precipitate(s) formed when solutions of na2so4(aq), ba(no3)2(aq), and nh4clo4(aq) are mixed.
Lostsunrise [7]

Answer : BaSO_{4} will be the precipitate which will be formed.


Explanation : When all the three solutions namely; NaSO_{4}  + Ba(NO_{3})_{2}  + NH_{4} ClO_{4} are mixed together a white precipitate of BaSO_{4} is formed as a product in the solution along with the soluble by product of Ammonium nitrate which is NH_{4} NO_{3} 

7 0
3 years ago
What is the product of the reaction of hydrobromic acid and 2-bromo-1-butene in the presence of acid and ether?
sergejj [24]

Answer: The major product of the reaction between Hydrobromic Acid and 2-bromo-1-butene in the presence of ether and acid is 2,2-dibromobutane.

Explanation:

The mechanism of the reaction is supported by the Markovnikov's rule which explains that in the addition reaction of alkenes by hydrogen-halogen compounds, the incoming halogen substituent goes to the more substituted Carbon. It can also be stated that incoming hydrogen atom goes to the Carbon with more Hydrogen atoms.

The only case when the reverse of Markovnikov's rule takes place is when Hydrogen peroxide is present and the addition reagent is HBr.

This case is not like that and it simply follows the Markovnikov's rule.

I'll add an attachment of the reaction to this now.

6 0
4 years ago
Read 2 more answers
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