How many Calories are there in 4600 Joules?

6. A dark-line spectrum is produced by

Sonbull [250]

Answer: HI

Explanation: GG

7 0

3 years ago

One mole of any gas has a volume of 24 dm3 or 24,000 cm3 at r.t.p .

brilliants [131]

Answer:

sorry I don't know heheh

7 0

3 years ago

A chemist fills a reaction vessel with 7.92 atm nitrogen (N2) gas, 2.02 atm hydrogen (H2) gas, and 2.11 atm ammonia (NH3) gas at

djverab [1.8K]

Answer: The Gibbs free energy of the given reaction is -40 kJ

Explanation:

The given chemical equation follows:

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

The equation for the standard Gibbs free change of the above reaction is:

$\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(NH_3(g))})]-[(1\times \Delta G^o_f_{(N_2(g))})+(3\times \Delta G^o_f_{(H_2(g))})]$

We are given:

$\Delta G^o_f_{(NH_3(l))}=-16.45kJ/mol\\\Delta G^o_f_{(H_2(g))}=0kJ/mol\\\Delta G^o_f_{(N_2(g))}=0kJ/mol$

Putting values in above equation, we get:

$\Delta G^o_{rxn}=[(2\times (-16.45))]-[(1\times (0))+(3\times (0))]\\\\\Delta G^o_{rxn}=-32.9kJ/mol$

The equation used to Gibbs free energy of the reaction follows:

$\Delta G=\Delta G^o+RT\ln Q_{eq}$

where,

$\Delta G$ = free energy of the reaction

$\Delta G^o$ = standard Gibbs free energy = -32.9 kJ/mol = -32900 J/mol (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314J/K mol

T = Temperature = $25^oC=[273+25]K=298K$

$Q_{eq}$ = Ratio of concentration of products and reactants at any time = $\frac{(p_{NH_3})^2}{(p_{H_2})^3\times p_{N_2}}$

$p_{NH_3}=2.11atm$

$p_{N_2}=7.92atm$

$p_{H_2}=2.02atm$

Putting values in above equation, we get:

$\Delta G=-32900J/mol+(8.314J/K.mol\times 298K\times \ln (\frac{(2.11)^2}{(2.02)^3\times 7.92}))\\\\\Delta G=-39553.04J/mol=--39.55kJ=-40kJ$

Hence, the Gibbs free energy of the given reaction is -40 kJ

7 0

3 years ago

How to keep pipes from freezing during power outage?.

Maurinko [17]

Answer: Running water, even at a trickle, helps prevent pipes from freezing. If you decide to use fuel-burning equipment, such as a kerosene heater, ensure it is vented to outside and kept clear of any vents. Keep garage doors closed if there are water supply lines in the garage.

Explanation:

8 0

2 years ago

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A flask contains 5.0g of neon gas at a temperature of 35°C. The pressure gauge indicates 0.37atm inside the flask. What is the v

DaniilM [7]

Answer:

The volume of the neon gas is 17.07 L.

Explanation:

The ideal gas equation describes the relationship among the four variables P, V, T, and n. An ideal gas is a hypothetical gas whose pressure-volume-temperature behavior can be completely accounted for by the ideal gas equation.

In order to calculate the volume, first we need to convert the grams of neon to moles:

28.18 g Ne ------ 1 mol Ne

5.0 g Ne---------- x= 0.25 mol Ne

Now, using the ideal gas equation we calculate the volume:

$pV= nRT$

$V= nRT ÷ p$

$V= (0.25 mol × 0.082 L.atm/mol.K × 308.15 K ÷ 0.37 atm$

V= 17.07 L

6 0

3 years ago