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ollegr [7]
3 years ago
7

Help me pls in question 7!!!

Mathematics
1 answer:
baherus [9]3 years ago
6 0

Answer:

a=2 b=3

Step-by-step explanation:

From ab^{0}=2 b^{0}=0  then a=2

ab^{1}=6 2b=6 b=3

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Solve for x.<br><br> -5(x – 4) = -30<br><br> Enter your answer in the box.<br><br> x =
Svetlanka [38]

Answer:

- 5(x - 4) = 30

- 5x + 20 = 30

- 5x = 30 - 20 = 10

x = 10  \div - 5

x =  - 2

3 0
3 years ago
Read 2 more answers
I need to know what the value is for x
hoa [83]
4/6 = x + 3/ 12 - x
4( 12 - x) = 6( x + 3)
48 - 4x = 6x + 18
-4x - 6x = 18 - 48
- 10x = -30
x = 3
6 0
4 years ago
A simple random sample with n = 58 provided a sample mean of 24.5 and a sample standard deviation of 4.4. (Round your answers to
nasty-shy [4]

Answer: (23.53, 25.47)

Step-by-step explanation:

The confidence interval for population mean(when population standard deviation is unknown) is given by :-

\overline{x} \pm\ t^*\dfrac{s}{\sqrt{n}}

, where \overline{x} = sample mean

n = sample size.

s = sample standard deviation.

t* = Critical value.

Given : \overline{x}=24.5

s= 4.4

Confidence level = 90% =0.090

Significance level = \alpha=1-0.90=0.10

Sample size : n= 58

Degree of freedom : df= n-1= 57

Using t-distribution table , the critical value :

t_{\alpha/2,\ df}= t_{0.05,\ 57}=1.6720

Then, the confidence interval will be :-

24.5 \pm\ (1.6720)\dfrac{4.4}{\sqrt{58}}

24.5 \pm\ (1.6720)\dfrac{4.4}{7.61577310586}

24.5 \pm\ 0.965995165263\approx24.5\pm0.97\\\\=(24.5-0.97,\ 24.5+0.97)\\\\=(23.53,\ 25.47)

Hence, a 90% confidence interval for the population mean = (23.53, 25.47)

6 0
4 years ago
A random sample of adults showed that of them have shopped at least once on the Internet. What is the (approximate) probability
Anvisha [2.4K]

Answer:

P = number of adults who have shopped at least once on the internet / number sampled adults

Step-by-step explanation:

Step 1

Let X be the number sampled adults

Let Y be the number of adults who have shopped at least once on the internet.

Let P be the probability that a randomly selected adult has shopped on the Internet.

Step 2

P = number of adults who have shopped at least once on the internet / number sampled adults

P = Y/X

An example:

If X is 1000 adults and Y is 200 adults therefore P = 200/1000 = 0.2

One can therefore infer that approximately 0.2 of the population surfs the internet at least once in a week.

5 0
3 years ago
The midpoint of AB is (-4,7) and point A is
levacccp [35]
Ok so, this one is a confusing one for me but what I recomend is going on a website call desmos , they have a graphing area there and use y=-4x-7 if I’m right, I do not know so don’t trust me on this
4 0
3 years ago
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