Answer:
Kindly check explanation
Step-by-step explanation:
Given that:
Cost per bracelet = 1.50
Cost per necklace = 2.25
Let :
number of necklace = n
Number of bracelet = b
Cost equation C ;
C = 1.5b + 2.25n
Number of necklace that could be sold for exactly $12
5 necklaces and 1 bracelet :
1.5 + 2.25(5) = 12.75
•2 necklaces and 5 bracelets:
1.5(5) + 2.25(2) = 12
• 3 necklaces and 3 bracelets
1.5(3) + 2.25(3) = 11.25
• 4 necklaces and 2 bracelets
1.5(2) + 2.25(4) = 12
• 3 necklaces and 5 bracelets
1.5(5) + 2.25(3) = 14.25
• 6 necklaces and no bracelets •
1.5(0) + 2.25(6) = 13.5
No necklaces and 8 bracelets
1.5(8) + 2.25(0) = 12
Amount charged per Tshirt = c
Setup fee = $40
Number of students in drama club = 21
Total cost of order = $187
Calculate C ;
Total order cost = set up fee + (cost per shirt * number of shirts)
Total order cost = 40 + 21c
187 = 40 + 21c
187 - 40 = 21c
147 = 21c
c = 147 / 21
C = 7
Hence cost per shirt = $7
Hello,
x^2-y^2=(x+y)(x-y)
x^3-y^3=(x-y)(x²+xy+y²)
Let's use Horner's division
.........|a^3|a^2.|a^1..........|a^0
.........|1....|5....|6..............|8....
a=p...|......|p....|5p+p^2....|6p+5p^2+p^3
----------------------------------------------------------
.........|1....|5+p|6+5p+p^2|8+6p+5p^2+p^3
The remainder is 8+6p+5p^2+p^3 or 8+6q+5q^2+q^3
Thus:
8+6p+5p^2+p^3 = 8+6q+5q^2+q^3
==>p^3-q^3+5p^2-5q^2+6p-6p=0
==>(p-q)(p²+pq+q²)+5(p-q)(p+q)+6(p-q)=0
==>(p-q)[p²+pq+q²+5p+5q+6]=0 or p≠q
==>p²+pq+q²+5p+5q+6=0
And here, Mehek are there sufficients explanations?
Jane addresses 200, while Louis addresses 100.
9514 1404 393
Answer:
No
Step-by-step explanation:
Put the value where the variable is and see if you get a true statement.
2(-4) -8 = -15
-8 -8 = -15 . . . . . . . false
-4 is <em>not a solution</em> to the equation
Answer:
0
Step-by-step explanation:
+25 for the first attempt but -25 for the second
