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3 years ago

!50 POINTS!

Mathematics

1 answer:

Strike441 [17]3 years ago

6 0

Answer:

A. 0

Step-by-step explanation:

<u>Given inequality:</u>

6 > z(10 - z)

<u>Solution:</u>

6 > 10z - z²
z² - 10z + 6 > 0
z² - 10z + 25 > 19
(z - 5)² > 19
z - 5 > √19 ⇒ z > 5 + √19 ⇒ z > 9.35
z - 5 < - √19 ⇒ z < 5 - √19 ⇒ z < 0.64

The only number satisfying this inequality is 0.

Correct choice is A

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The weekly ad for a local grocery store advertises a 5 pound bag of organic apples for $13.95. Round each rate to the nearest hu

beks73 [17]

Answer:

$2.79 per pound of apples.

0.36 pounds per dollar.

The unit rate representing cost of per pound apples is typically used.

Step-by-step explanation:

We have been given that the weekly ad for a local grocery store advertises a 5 pound bag of organic apples for $13.95.

Since we know when rates are expressed as a quantity of 1, such as 100 meter per second or 5 miles per hour, they are called unit rates. We need to have 1 in our denominator to express two quantities as unit rate.

Let us find the unit rate in terms of cost of per pound bag of apples.

$\text{Unit rate as the cost of organic apples per pound}=\frac{\$13.95}{5 \text{ pounds of organic apples}}$

$\text{Unit rate as the cost of organic apples per pound}=\frac{\$2.79} {\text{ pound of organic apples}}$

Therefore, our unit rate will be $2.79 per pound of apples.

Let us find unit rate of pounds of apples per dollar.

$\text{Unit rate as the pounds of organic apples per dollar}=\frac{5\text{ pounds of organic apples}}{\$13.95}$

$\text{Unit rate as the pounds of organic apples per dollar}=\frac{0.3584 \text{ pounds of organic apples}}{\$}$

$\text{Unit rate as the pounds of organic apples per dollar}\approx \frac{0.36 \text{ pounds of organic apples}}{\$}$

Therefore, our another unit rate will be 0.36 pounds per dollar.

Since, we purchase apples or other items according to their price per piece or their price per pound in our daily life, therefore, the unit rate representing cost of per pound apples is typically used.

3 0

3 years ago

Read 2 more answers

Plzzzzzzzzz helpppppppp meeeeeeeeee

dalvyx [7]

Answer:

spenca idk the answer g

5 0

3 years ago

3. The following sequence shows the number of pushups Kendall did each week, starting with her first week of exercising: 6, 18,

Alona [7]

{{{ THE BOLDED CHARACTERS SHOULD BE SMALL. }}}

SEQUENCE: 6, 18, 54, 162

18/6 = 3

54/18 = 3

162/54 = 3

then, r (common ratio) = 3

_________________________________________

RECURSIVE RULE: r = 3

an = a(n - 1) × r [formula]

ANSWER: an = a(n - 1) × 3

_________________________________________

ITERIATIVE RULE: r = 3, a1 = 6

an = a1 × r^(n - 1) [formula] [ ^(n-1) is an exponent]

ANSWER: an = 6 × 3^(n - 1)

4 0

3 years ago

A particular variety of watermelon weighs on average 20.4 pounds with a standard deviation of 1.23 pounds. Consider the sample m

love history [14]

Answer:

a) The expected value of the sample mean weight is 20.4 pounds.

b)The standard deviation of the sample mean weight is 0.123.

c) There is a 14.46% probability the sample mean weight will be less than 20.27.

d) This value is $c = 20.6153$ .

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A particular variety of watermelon weighs on average 20.4 pounds with a standard deviation of 1.23 pounds. This means that $\mu = 20.4, \sigma = 1.23$