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3 years ago

The answer to this question

Mathematics

2 answers:

beks73 [17]3 years ago

8 0

100000001 is the answer

PilotLPTM [1.2K]3 years ago

7 0

10000000 + 1 = 10000001
Duh

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The price of a new 4G-cell phone is $200 in store A and $240 in store B. If you get 15% discount in store B, where would you buy

satela [25.4K]

Answer:

Store A

Step-by-step explanation:

Store A costs $200.

Store B costs $240, with a 15% discount.

To solve how much the discount is, you do -

$240*0.85=204$

Since Store A is still cheaper, choose Store A.

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3 years ago

Is there a difference between the 80th percentile and the top 80%?

Aleksandr [31]

<span>Actually, yes there is. Being in the 80th percentile means that you are smart than 80% of the people (i.e. out of 100 people, you would be smarter than 80 of them). However being in the top 80% means that you are a part of the 80 smartest people out that same 100. </span>

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3 years ago

I need help I will rate you brainliest

Tems11 [23]

Answer:

it would be subtraction

Step-by-step explanation:

Because if you are trying to get you would do 2-2 to get 0 and have x by itself

3 0

3 years ago

Read 2 more answers

Find the area of the shaded region

o-na [289]

so hmmm let's get the area of the whole hexagon, and then get the area of the circle inside it, then <u>subtract the area of the circle from that of the hexagon's</u>, what's leftover is what we didn't subtract, namely the shaded part.

$\textit{area of a regular polygon}\\\\ A=\cfrac{1}{4}ns^2\cot\stackrel{\stackrel{degrees}{\downarrow }}{\left( \frac{180}{n} \right)}~ \begin{cases} n=\textit{number of sides}\\ s=\textit{length of a side}\\[-0.5em] \hrulefill\\ n=\stackrel{hexagon}{6}\\ s=\frac{9}{2} \end{cases}\implies A=\cfrac{1}{4}(6)\left( \cfrac{9}{2} \right)^2 \cot\left( \cfrac{180}{6} \right)$

$A=\cfrac{1}{4}(6)\cfrac{9^2}{2^2} \cot(30^o)\implies A=\cfrac{243}{8}\cot(30^o)\implies A=\cfrac{243\sqrt{3}}{8} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=\frac{4}{5} \end{cases}\implies A=\pi \left( \cfrac{4}{5} \right)^2\implies A=\cfrac{16\pi }{25} \\\\[-0.35em] ~\dotfill$

$\stackrel{\textit{area of the hexagon}}{\cfrac{243\sqrt{3}}{8}}~~ - ~~\stackrel{\textit{area of the circle}}{\cfrac{16\pi }{25}}\implies \cfrac{6075\sqrt{3}-128\pi }{200}$

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2 years ago

HELP ME FAST!!!!!Plz my computers about to go dead

Delvig [45]

It’s 4/15
Answer = 3 3/4
I hope that helps :)

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2 years ago

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