Since, the polygon is a trapezoid made up of a rectangle and a right triangle. Therefore, according to the question, the figure of the polygon is attached.
Since, perimeter is the total length of the outer boundary of the figure. Therefore,
Perimeter of the polygon is
Area of the polygon = Area of Rectangle + Area of Triangle
![=[(18) \times (15)] + [(\frac{1}{2}) \times (8) \times (15)]](https://tex.z-dn.net/?f=%3D%5B%2818%29%20%5Ctimes%20%2815%29%5D%20%2B%20%5B%28%5Cfrac%7B1%7D%7B2%7D%29%20%5Ctimes%20%288%29%20%5Ctimes%20%2815%29%5D)
![=270 + [(\frac{8}{2}) \times (15)]](https://tex.z-dn.net/?f=%3D270%20%2B%20%5B%28%5Cfrac%7B8%7D%7B2%7D%29%20%5Ctimes%20%2815%29%5D)
![=270 + [4 \times (15)]](https://tex.z-dn.net/?f=%3D270%20%2B%20%5B4%20%5Ctimes%20%2815%29%5D)
Answer: if it is simply then the answer is 3x^3+14x^2-17x+14
Step-by-step explanation:
Answer:
x = 6
Step-by-step explanation:
EG = 59
EF = 8x - 14
FG = 4x + 1
to find the value of x
EF + FG = EG (same line)
8x - 14 + 4x + 1 = 59
12x -13 = 59
12x = 59 + 13
12x = 72
x = 72 ÷ 12
x = 6
You can even cross check for correct answer
EF + FG = EG
instead of x place the x's value we got
8x - 14 + 4x + 1 = 59
8 (6) - 14 + 4 (6) + 1 = 59
48 - 14 + 24 + 1 = 59
34 + 25 = 59
59 = 59
CROSS - CHECKED
Answer:
45 i think i dont know
Step-by-step explanation:
m
∠
2
=
x
holds true.
Complementary angles have a sum of
90
˚
. Thus, if
∠
1
and
∠
2
are complementary,
m
∠
1
+
m
∠
2
=
90
Substitute the equivalent forms of these angle measurements
(
x
,
x
)
.
x
+
x
=
90
Solve algebraically.
2
x
=
90
x
=
45
Each angle is
45
˚
.
