The solution would be like this for this specific problem:
Given:
N = 256
Sample Mean = $35,420
Standard Deviation = $2,050
Find:
Standard Error of Mean = ?
The
formula for the standard error of the mean is:
<span>Om
= o / sqrt(N)</span>
<span>Om
= the </span>standard deviation of the sampling
distribution of the mean
where
o = standard deviation of the sampling distribution of a statistic
N
= sample size
<span>So
substituting the formula with the given:
Om = $2,050 / sqrt(256)</span>
<span>Om
= $2,050 / 16</span>
= $128.125
Therefore, the sample standard error of the mean is
$128.125.
Step-by-step explanation:
Add 8n to both sides to get
8n-67 = 5
then add 67
8n = 5+67 = 72
divide by 8
n = 9
Answer:
<em>The capacity of the cistern is</em> ![1.2231~m^3](https://tex.z-dn.net/?f=1.2231~m%5E3)
<em>The volume of iron used is</em> ![0.0891~m^3](https://tex.z-dn.net/?f=0.0891~m%5E3)
Step-by-step explanation:
<u>Volume</u>
The volume of a rectangular box of dimensions x,y,z is given by:
V = x.y.z
The external dimensions of the rectangular cistern are 1.35 m, 1.08 m, and 0.90 m, thus the external volume is:
![V_e=1.35*1.08*0.90=1.3122~m^3](https://tex.z-dn.net/?f=V_e%3D1.35%2A1.08%2A0.90%3D1.3122~m%5E3)
The cistern is made of iron 2.5 cm= 0.025 thick, thus the internal dimensions are:
1.35 - 0.025 = 1.325 m
1.08 - 0.025 = 1.055 m
0.90 - 0.025 = 0.875 m
The internal volume is:
![V_i=1.325*1.055*0.875](https://tex.z-dn.net/?f=V_i%3D1.325%2A1.055%2A0.875)
![V_i=1.2231~m^3](https://tex.z-dn.net/?f=V_i%3D1.2231~m%5E3)
The capacity of the cistern is 1.2231~m^3
The volume of iron used is the difference between the external and the internal volumes:
![V_{iron}=1.3122~m^3-1.2231~m^3](https://tex.z-dn.net/?f=V_%7Biron%7D%3D1.3122~m%5E3-1.2231~m%5E3)
![V_{iron}=0.0891~m^3=89.1~lt](https://tex.z-dn.net/?f=V_%7Biron%7D%3D0.0891~m%5E3%3D89.1~lt)
The volume of iron used is ![0.0891~m^3](https://tex.z-dn.net/?f=0.0891~m%5E3)
252$ plus the the gas grill is your answer I think