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RUDIKE [14]
3 years ago
8

Which expression is equivalent to 3x + 5 y + y - 2y​

Mathematics
1 answer:
LuckyWell [14K]3 years ago
6 0

Answer:

Step-by-step explanation:

3x+5y+y-2y = 3x +y(5+1-2)

                   =  3x +4y

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Name two equivalent fractions for each <br> 2/4<br> 1/3<br> 1/4
Scrat [10]
2/4=1/2 and 4/8
1/3=2/6 and 3/9
1/4=2/8 and 3/12
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A box measures 20 inches wide by 14 inches deep. The height of the box is two feet. What is the volume of the box? Remember two
Jobisdone [24]

Answer:

6,720 inches or 560 feet

Step-by-step explanation:

20 x 14 x 24 = said number above.

Remember volume is just length times width times height.

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3 years ago
When counting from 5 what number follows 4
Kryger [21]

Answer:

3 is the answer

Step-by-step explanation:

5.........4............3..............2...............1

so 3 follows 4

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The Florida tourism board surveyed people on their favorite vacation cities. Half of the people said Orlando, 1/4 said Miami, 1/
solniwko [45]
352? I'm not so sure.
7 0
3 years ago
HELP PLEASE <br><br>must show work <br><br>I have the answer just need to show work​
Kazeer [188]

Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) 8+6x^4

here we can see, both numbers are divisible by 2, so taking 2 common

=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)

It cannot be further simplified because both number donot have same bases.

3.4n^9 + 12 n

We can take 4n common

=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)

5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

= -3(4a +1)

7. 12n^5 + 16n^3

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

4n^3( 3n^2 + 4)

9. 5k^2 - 40k+10

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

=5(k^2 - 8k + 2)

11.-60 + 60n^2 +50n^3

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

=10(-6 + 6n^2 +5n^3)

13. -36n^3 -12n-28

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

=-4(9n^3 + 3n +7)

15. 63n^3+81n+18

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

=9(7n^3 + 9n + 2)

17. -24a^2b^2 + 36ab-60a

=6a(-4ab^2+6b-10)

3 0
3 years ago
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