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FromTheMoon [43]
2 years ago
10

A shopkeepers bought 500 glass tumblers at rs 40 each . 20 glass tumblers were broken and he sold the rest at rs 45 each. Find h

is profit or loss percent
if you will solve this questions in copy and send me pictures of the answer then it will be very helpful for me please​
Mathematics
1 answer:
Alona [7]2 years ago
4 0

500 at 40 each = £20000

To make a profit he needs to make more than £20000

20 broke so he sold 500-20 = 480 at 45 each.

480 x 45 = 21600

Profit = 21600 -20000 = 1600

His profit was £1,600

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Write the ratio:2 2/5to 5 1/5 as a fraction in the lowest terms
yuradex [85]
2 2/5=12:5
5 1/5= 26:5
12:26:5
I think.
4 0
3 years ago
19. A $50 bottle of perfume holds 8 ounces. A $110 bottle holds 17 oz. Find the unit price for
jok3333 [9.3K]
50 divided by 8 = 6.25
1oz perfume = $6.25
110 divided by 17 = 6.4705
1oz perfume = $6.4705
Therefore the second option is cheaper
7 0
3 years ago
A media poll of 500 air travelers surveyed in national airports found that 370 favor tighter security procedures in boarding pla
serg [7]

Answer:

92% Confidence interval:  (0.7078,0.7722)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 500

Number of travelers who favor tight security, x = 370

\hat{p} = \dfrac{x}{n} = \dfrac{370}{500} = 0.74

92% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.08} = \pm 1.645

Putting the values, we get:

0.74\pm 1.645(\sqrt{\dfrac{0.74(1-0.74)}{500}}) = 0.74\pm 0.0322\\\\=(0.7078,0.7722)

3 0
3 years ago
MULTIPLE CHOICE QUESTION
nevsk [136]

Answer:

2

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
What are the potential zeros of f(x)=6x^4+ 2x^3 - 4x^2 +2?
Dmitry_Shevchenko [17]

The potential zeros of f(x)=6x^4+ 2x^3 - 4x^2 +2 are ±(1, 1/2, 1/3, 1/6, 2, 2/3)

<h3>How to determine the potential zeros of the function f(x)?</h3>

The function is given as:

f(x)=6x^4+ 2x^3 - 4x^2 +2

For a function P(x) such that

P(x) = ax^n +...... + b

The rational roots of the function p(x) are

Rational roots = ± Possible factors of b/Possible factors of a

In the function f(x), we have:

a = 6

b = 2

The factors of 6 and 2 are

a = 1, 2, 3 and 6

b = 1 and 2

So, we have:

Rational roots = ±(1, 2)/(1, 2, 3, 6)

Split the expression

Rational roots = ±1/(1, 2, 3, 6)/ and ±2/(1, 2, 3, 6)

Evaluate the quotient

Rational roots = ±(1, 1/2, 1/3, 1/6, 2, 1, 2/3, 1/3)

Remove the repetition

Rational roots = ±(1, 1/2, 1/3, 1/6, 2, 2/3)

Hence, the potential zeros of f(x)=6x^4+ 2x^3 - 4x^2 +2 are ±(1, 1/2, 1/3, 1/6, 2, 2/3)

The complete parameters are:

The function is given as:

f(x) = 3x^3 + 2x^2 + 3x + 6

The potential zeros of f(x)=6x^4+ 2x^3 - 4x^2 +2 are ±(1, 1/2, 1/3, 1/6, 2, 2/3)

Read more about rational roots at

brainly.com/question/17754398

#SPJ1

4 0
2 years ago
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