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3 years ago

PLEASE TRY TO HELP I'M STRUGGLING

Mathematics

2 answers:

Anvisha [2.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)

The equation of the given line is

7x+4y=3

4y = - 7x + 3

y = -7x/4 + 3/4

Comparing with the slope intercept form, slope = -7/4

If the line passing through the given point is perpendicular to the given line, it means that its slope is the negative reciprocal of the slope of the given line.

Therefore, the slope of the line passing through (6,-9) is 4/7

To determine the intercept, we would substitute m = 4/7, x = 6 and y = -9 into y = mx + c. It becomes

- 9 = 4/7×6 + c = 24/7 + c

c = - 9 - 24/7 = -87/7

The equation becomes

y = 4x/7 - 87/7

Orlov [11]3 years ago

5 0

Answer:

Step-by-step explanation:

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Ulleksa [173]

Answer:

<h3><em><u>The mass of a lead cube whose </u></em><em><u>side </u></em><em><u>have length 1.5 cm is 40.5 </u></em><em><u>grams</u></em></h3>

Step-by-step explanation:

<u>1. Let's review the information given to</u>

<u>1. Let's review the information given tous to answer the question correctly:</u>

<u>1. Let's review the information given tous to answer the question correctly:Mass of the cube made out of lead</u> = 12

= 12grams

Side of the cube <em>= 1 cm</em>

2. <em><u>What would be the mass of a lead</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?For answering the question, let's</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?For answering the question, let'scalculate the volume of the cube and</u></em>

<em><u>What would be the mass of a leadcube whose sides have length 1.5 cm?For answering the question, let'scalculate the volume of the cube andthen its density, this way:</u></em>

<h3>Volume = Height* Width * Length</h3><h3>Volume=1*1*1</h3><h3>Volume =1 cm</h3>

Let's recall the formula of the density:

Density Mass/Volume, therefore:

Density of the lead <em><u>= 12/1= 12 gr/</u></em><em><u>cm</u></em>

<em><u>Now, let's calculate the volume of the</u></em>

<em><u>Now, let's calculate the volume of thesecond cube:</u></em>

<h3><em>Volume = Height Width Length</em></h3><h3><em>Volume = Height Width LengthVolume 1.5 * 1.5 1.5</em></h3><h3><em>Volume = Height Width LengthVolume 1.5 * 1.5 1.5Volume =3.375 cm3</em></h3>

<u>Finally, let's calculate the mass, using</u>

<u>Finally, let's calculate the mass, usingthe density of the lead we already</u>

<u>Finally, let's calculate the mass, usingthe density of the lead we alreadyknow:</u>

<h3>Density = Mass/Volume</h3><h3><em>12 Mass/3.375</em></h3><h3><em>12 Mass/3.375Mass 12 *3.375</em></h3><h3><em>12 Mass/3.375Mass 12 *3.375Mass = 40.5 gramss</em></h3>

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