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3 years ago

PLEASE TRY TO HELP I'M STRUGGLING

Mathematics

2 answers:

Anvisha [2.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis)

The equation of the given line is

7x+4y=3

4y = - 7x + 3

y = -7x/4 + 3/4

Comparing with the slope intercept form, slope = -7/4

If the line passing through the given point is perpendicular to the given line, it means that its slope is the negative reciprocal of the slope of the given line.

Therefore, the slope of the line passing through (6,-9) is 4/7

To determine the intercept, we would substitute m = 4/7, x = 6 and y = -9 into y = mx + c. It becomes

- 9 = 4/7×6 + c = 24/7 + c

c = - 9 - 24/7 = -87/7

The equation becomes

y = 4x/7 - 87/7

Orlov [11]3 years ago

5 0

Answer:

Step-by-step explanation:

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A random sample of 500 of these people is drawn, of whom 194 turn out to be currently enrolled in college. Estimate the percenta

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$0.388 - 2.00\sqrt{\frac{0.388(1-0.388)}{500}}=0.344$

$0.388 + 2.00\sqrt{\frac{0.388(1-0.388)}{500}}=0.432$

The 95.5% confidence interval would be given by (0.344;0.432)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The estimated proportion on this case is given by:

$p = \frac{X}{n}= \frac{194}{500}=0.388$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95.5% of confidence, our significance level would be given by $\alpha=1-0.955=0.045$ and $\alpha/2 =0.0225$ . And the critical value would be given by: