Question

Solving systems of 3 equations 2x-y-3z=4 4x+2y+z=10 4x-y+4z=-8

Answer 1

The solution to the system of equation is (1, 4,-2)

Solving system of equations

Given the following system of equation below

2x-y-3z=4

4x+2y+z=10

4x-y+4z=-8

Subtract equations 2 and 3 to have:

3y - 3z = 18

y - z = 6

y =6 + z ............. 4

Also multiply equation 1 by 2 and subtract from 2 to have;

2x-y-3z=4

4x+2y+z=10

----------------------------

-4y - 7z = -2 .......... 5

Substitute 4 into 5 to have

-4(6+z) - 7z = -2

-24 - 4z - 7z = -2
-24-11z = -2

-11z = 22

z = -2

Substitute x = -2 into y =6 + z

y = 6 - 2

y = 4

Determine the value of x

2x - y - 3z = 4

2x - 4 + 6 = 4

2x = 4 - 2

2x = 2

x = 1

Hence the solution to the system of equation is (1, 4,-2)

Learn more on system of equation here: brainly.com/question/25976025

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