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1 answer:
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You have two equations.
since the second is already isolated, sub in x-4 for every y in equation 1 so that
![x^{2} - 4 [(x-4)^{2}] =16 ](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20-%204%20%5B%28x-4%29%5E%7B2%7D%5D%20%3D16%0A%20)
expand, collect like terms, factor to find x, then plug x value back into original equation to find y
since the second is already isolated, sub in x-4 for every y in equation 1 so that
expand, collect like terms, factor to find x, then plug x value back into original equation to find y
Answer:
The Greatest possible value of one of the integer is 140.
Step-by-step explanation:
Given: The average (arithmetic mean) of five different positive integers is 30.
To find: What is the greatest possible value of one of these integers?
Explanation: we are given that the arithmetic mean of five positive integer
is 30.
Let the five positive integers are A,B,C,D,E
The arithmetic mean :
=30.
On multiplying both side by 5.
A+B+C+D+E =150.
The least values of A ,B,C and D can be 1 ,2,3,4.
Then : 1 +2+3+4+E =150
On simplification 10+E =150
On subtraction both side by 10 we get
E = 140 .
Therefore, the Greatest possible value of one of the integer is 140.