'll use the binomial approach. We need to calculate the probabilities that 9, 10 or 11
<span>people have brown eyes. The probability that any one person has brown eyes is 0.8, </span>
<span>so the probability that they don't is 1 - 0.8 = 0.2. So the appropriate binomial terms are </span>
<span>(11 C 9)(0.8)^9*(0.2)^2 + (11 C 10)(0.8)^10*(0.2)^1 + (11 C 11)(0.8)^11*(0.2)^0 = </span>
<span>0.2953 + 0.2362 + 0.0859 = 0.6174, or about 61.7 %. Since this is over 50%, it </span>
<span>is more likely than not that 9 of 11 randomly chosen people have brown eyes, at </span>
<span>least in this region. </span>
<span>Note that (n C r) = n!/((n-r)!*r!). So (11 C 9) = 55, (11 C 10) = 11 and (11 C 0) = 1.</span>
I got 12.654 I'm not sure it is right though.
Answer:
B.2
Step-by-step explanation:
To make ΔA'B'C' from ΔABC, we need to use t
he scale factor =|A'B'|/|AB|=10/5=2
Answer:
Step-by-step explanation:
<u>Given:</u>
- Total number = 700
- Off grid class = 450
- Online class = 320
- Both = 275
<u>Based on the given we find the following</u>
1) <u>Off-grid class only:</u>
3) <u>Online class only:</u>
2) <u>None of the classes:</u>
- 700 - (175 + 275 + 45) = 205
4) <u>Not online:</u>
5) <u>Not off-grid:</u>
Answer:
Rise = 15.
Run = 1.
Step-by-step explanation:
Hope this helps!
=)
