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amid [387]
4 years ago
8

Simplify the radical

Mathematics
2 answers:
Juliette [100K]4 years ago
8 0

\sqrt[4]{81x^{20}y^{24}}\\\\Use\ (a^n)^m=a^{nm}\\\\=\sqrt[4]{3^4x^{5\cdot4}y^{6\cdot4}}=\sqrt[4]{3^4(x^5)^4(y^6)^4}\\\\Use\ \sqrt[n]{ab}=\sqrt[n]{a}\cdot\sqrt[n]{b}\\\\=\sqrt[4]{3^4}\cdot\sqrt[4]{(x^5)^4}\cdot\sqrt[4]{(y^6)^4}\\\\Use\ \sqrt[n]{a^n}=a\\\\=3|x^5|y^6\\\\Answer:\ \boxed{b.\ 3|x^5|y^6}\\\\Why\ |x^5|?\ Beacause\ \sqrt[4]{x^{20}}\geq0\to x^5\geq0\ if\ x\geq0\ and\ x^5

Vinil7 [7]4 years ago
4 0

I believe A should be the answer, hope that helps.

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Can someone please do this ill mark brainliest
Svet_ta [14]

Answer:

-60  im pretty sure this is it

                                 

8 0
4 years ago
Least common multiple of 70, 60, and 50
goldenfox [79]
70 = 7 x 2 x 5
60 = 2² x 3 x 5
50 =  2 x 5²
 
LCM = 2 x 3 x 5 x 7  = 210

Answer: LCM = 210
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artcher [175]
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irinina [24]

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6 0
3 years ago
Find the mean median mode and range for the following data 77 60 59 70 89 95
Advocard [28]

Answer:

Mean = 75

Median = 73.5

Mode = 95

Range = 36

Step-by-step explanation:

Given:

  • 77,60,59,70,89,95

Sort:

  • 59,60,70,77,89,95

To find:

  • Mean
  • Median
  • Mode
  • Range

Mean:

\displaystyle \large{\dfrac{1}{n}\sum_{i =1}^n x_i = \dfrac{x_1+x_2+x_3+...+x_n}{n}}

Sum of all data divides by amount.

\displaystyle \large{\dfrac{59+60+70+77+89+95}{6}=\dfrac{450}{6}}\\\\\displaystyle \large{\therefore mean=75}

Therefore, mean = 75

Median:

If it’s exact middle then that’s the median. However, if two data or values happen to be in <em>middle</em>:

\displaystyle \large{\dfrac{x_1+x_2}{2}}

From 59,60,70,77,89,95, since 70 and 77 are in middle:

\displaystyle \large{\dfrac{70+77}{2} = \dfrac{147}{2}}\\\displaystyle \large{\therefore median = 73.5}

Therefore, median = 73.5

Mode:

The highest value or/and the highest amount of data. Mode can have more than one.

From sorted data, there are no repetitive data nor same data. Consider the highest value:

Therefore, mode = 95

Range:

\displaystyle \large{x_{max}-x_{min}} or highest value - lowest value

Thus:

\displaystyle \large{95-59 = 36}

Therefore, range = 36

7 0
2 years ago
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