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kipiarov [429]
3 years ago
15

If Linnia Bought some flats for flowers and each flat hold 9 flowers, and she has planted 10 flowers, would 9x + 10 be a reasona

ble algebraic expression to the problem?
Mathematics
1 answer:
Elena-2011 [213]3 years ago
4 0

Answer:

no because 9x means 9 times what ever x is so 9x +10 is not reasonable

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There are twelve people on the jury there were 4more man than women how many man were <br>there/
irina1246 [14]
x-the \ number \ of \ women \\ x+4 -the \ number \ of \ men \\\\ x+x+4=12 \\\\ 2x+4=12 \\\\ 2x=12-4 \\\\ 2x=8 \\\\ \boxed{x=\frac{8}{2}=4 \ women} \\\\ x+4= \\\\ = 4+4\to\boxed{8 \ men}
4 0
3 years ago
Read 2 more answers
6/7 / 1/2 plz give correct answer
3241004551 [841]
It’s 0.166.
1/6= 0.166
( 6 | 1. 000)
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6 0
3 years ago
Use substitution to solve each system of equations:<br><br> x=y+6<br> x+y=10
Fittoniya [83]
= (y+6) +y =10
= 2y + 6 = 10
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5 0
3 years ago
write two equations that when graphed look like this *see image*. please help its due soon and i will give ya 75 points for answ
Zigmanuir [339]

The graph is showing the equation of circle x²+y²=4

<h3>What is a circle?</h3>

A circle is a two-dimensional geometry on the plane having a centre point and the circular line is drawn equidistant from the centre point.

The given graph in the question represents the equation of the circle cutting the points on the x-axis and y-axis at 4 which is the radius of the circle.

The equation will be as follows:-

x²+y²=4

Hence the graph is showing the equation of circle x²+y²=4

To know more about circles follow

brainly.com/question/24375372

#SPJ1

8 0
2 years ago
WILL GIVE BRAINLIEST!!!!
Vesna [10]

(2^8 \times 5^{-5} \times 19^0)^{-2} \times (\dfrac{5^{-2}}{2^3})^4 \times 2^{28} =

= 2^{-16} \times 5^{10} \times 1 \times \dfrac{5^{-8}}{2^{12}} \times 2^{28}

= 2^{-16} \times 5^{10} \times 5^{-8} \times 2^{-12} \times 2^{28}

= 2^{-16} \times 2^{-12} \times 2^{28} \times 5^{10} \times 5^{-8}

= 2^{-16-12+28} \times 5^{10-8}

= 2^{0} \times 5^{2}

= 1 \times 25

= 25

7 0
3 years ago
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