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just olya [345]
3 years ago
9

Which ordered pair describes the location of point P?

Mathematics
1 answer:
Reptile [31]3 years ago
6 0
Coordinates are written (x,y). So find P on the graph. Start at the origin, (0,0), and go left 2 units, sp you're right under P. Since you went left, it's negative, x=-2. Then just go up until you get to P, y=3. So you end up with P is at (-2,3). Hope this helps!
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During the Playoff the schools football team has on average 30% their games than during the regular season. The average for this
exis [7]

Answer:12000

Step-by-step explanation:

During the Playoff the schools football team has on average 30% their games than during the regular season

The average for this year's playoffs attendance was 15,600 fans

To get the number of fans during a regular season goes thus:

Since there is an increase of 30%, we add 100% to 30% which gives:

100% + 30% = 130%

= 15600 ÷ 130%

= 15600 ÷ 130/100

= 15600 × 100/130

= 15600 × 0.7692

= 12000

There are 12000 fans during a regular season

5 0
3 years ago
Read 2 more answers
Which point is a solution to the inequality shown in this graph? (3,-1) (-3,-3)
Ne4ueva [31]

Answer: try c (1,5)

Step-by-step explanation: hey eri-chan

5 0
3 years ago
find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM​
Snezhnost [94]

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

  • Given - <u>A </u><u>trapezium</u><u> </u><u>ABCD </u><u>with </u><u>non </u><u>parallel </u><u>sides </u><u>of </u><u>measure </u><u>1</u><u>5</u><u> </u><u>cm </u><u>each </u><u>!</u><u> </u><u>along </u><u>,</u><u> </u><u>the </u><u>parallel </u><u>sides </u><u>are </u><u>of </u><u>measure </u><u>1</u><u>3</u><u> </u><u>cm </u><u>and </u><u>2</u><u>5</u><u> </u><u>cm</u>

  • To find - <u>Area </u><u>of </u><u>trapezium</u>

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

<u>Construction</u><u> </u><u>-</u>

draw \: CE \: \parallel \: AD \:  \\ and \: CD \: \perp \: AE

Now , we can clearly see that AECD is a parallelogram !

\therefore AE = CD = 13 cm

Now ,

AB = AE + BE \\\implies \: BE =AB -  AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm

Now , In ∆ BCE ,

semi \: perimeter \: (s) =  \frac{15 + 15 + 12}{2}  \\  \\ \implies \: s =  \frac{42}{2}  = 21 \: cm

Now , by Heron's formula

area \: of \: \triangle \: BCE =  \sqrt{s(s - a)(s - b)(s - c)}  \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)}  \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21}  \: cm {}^{2}

Also ,

area \: of \: \triangle \:  =  \frac{1}{2}  \times base \times height \\  \\\implies 18 \sqrt{21} =  \: \frac{1}{\cancel2}  \times \cancel12  \times height \\  \\ \implies \: 18 \sqrt{21}  = 6 \times height \\  \\ \implies \: height =  \frac{\cancel{18} \sqrt{21} }{ \cancel 6}  \\  \\ \implies \: height = 3 \sqrt{21}  \: cm {}^{2}

<u>Since </u><u>we've </u><u>obtained </u><u>the </u><u>height </u><u>now </u><u>,</u><u> </u><u>we </u><u>can </u><u>easily </u><u>find </u><u>out </u><u>the </u><u>area </u><u>of </u><u>trapezium </u><u>!</u>

Area \: of \: trapezium =  \frac{1}{2}  \times(sum \: of \:parallel \: sides) \times height \\  \\ \implies \:  \frac{1}{2}  \times (25 + 13) \times 3 \sqrt{21}  \\  \\ \implies \:  \frac{1}{\cancel2}  \times \cancel{38 }\times 3 \sqrt{21}  \\  \\ \implies \: 19 \times 3 \sqrt{21}  \: cm {}^{2}  \\  \\ \implies \: 57 \sqrt{21}  \: cm {}^{2}

hope helpful :D

6 0
1 year ago
Brook makes this conjecture: Because the angles are equal, the proportion of area of each sector relative to the area of the giv
AnnZ [28]

Answer:

The Brooks conjecture is true as the proportion of the area of a sector to the area of a circle is only dependent on the angle.

Step-by-step explanation:

The area of a sector for a radius r and an angle θ is given as

\Delta Sector=\dfrac{1}{2}r^2\theta

Whereas the area of a circle for a radius r is given as

\Delta Circle=\pi r^2

Now the ratio is given as

\dfrac{\Delta Sector}{\Delta Circle}=\dfrac{\dfrac{1}{2}r^2\theta}{\pi r^2}

Here as r is the radius of the circle and it is the same therefore the above ratio is simplified to

\dfrac{\Delta Sector}{\Delta Circle}=\dfrac{\theta}{2\pi }

Here as π is constant the only variable here is θ. Thus according to Brooks conjecture when the angles are equal, the proportion of area of each sector relative to the area of the given circle is also equal is true.

6 0
3 years ago
4 adults consumed food costing $60 for 3days. For the same food cost ,what would be the cost of food consumed by 7 adults for 5d
salantis [7]

Answer:

$175

Step-by-step explanation:

$60÷3÷4 =5

$5 is the cost of one adult's food for one day.

$5×7×5

=$175

$175 is the cost of food consumed by 7 adults for 5 days.

3 0
2 years ago
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