Can someone help me with this problem ?

Mathematics

1 answer:

Katena32 [7]3 years ago

5 0

Answer:

What is the problem?

Step-by-step explanation:

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Simplify this expression completely: -5r-(6r-1)

Ivenika [448]

$\text{Hello there!}\\\\\text{Solve:}\\\\-5r-(6r-1)\\\\\text{Distribute the negative to the numbers inside the parenthesis}\\\\-5r-6r+1\\\\\text{Combine like terms}\\\\-11r+1\\\\\boxed{-11r+1}$

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kondor19780726 [428]

$\bf \cfrac{4a}{3}-\cfrac{b}{4}=6
\qquad \qquad 
\cfrac{5a}{6}+b=13
\\\\\\
\textit{let us remove the denominators off those folks}\\
\textit{by multiplying the first one by 12, both sides}\\
\textit{and the second one by 6, both sides, thus}
\\\\\\
12\left( \cfrac{4a}{3}-\cfrac{b}{4} \right)=12(6)\implies 16a-4b=72
\\\\\\
6\left( \cfrac{5a}{6}+b \right)=6(13)\implies 5a+6b=78$

$\bf \textit{now, let's do the elimination}
\\\\

\begin{array}{llll}
16a-4b=72&\boxed{\times 3}\implies &48a-\underline{12b}=216\\\\
5a+6b=78&\boxed{\times 2}\implies &10a+\underline{12b}=156\\
&&--------\\
&&58a+0\quad=372
\end{array}$

solve for "a", once you get "a", plug it back into either equation to get "b"

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Step-by-step explanation:

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