II. f(x) doubles for each increase of 1 in the x values. Thus, r must be 2, and so we our ar^1 = 6 from ( I ) above becomes f(x) = a*2^x. Applying the restriction ar^1 = 6 results in f(1) = a*2^1 = 6, or a = 3.
Then f(x) = ar^x becomes f(x) = 3*2^2 (Answer A)
Answer:
1. have se x
Step-by-step explanation:
Answer:
D. 267.9 in3
Step-by-step explanation:
So we know the diameter is 16 inches.
So we need to find the radius and we do that by: 16/2 = 8 then it is reduced by half: 8/2 = 4
Now we need to find the volume.
V= 4/3 times 3.14 times 4^3= 268.08
So we would need to round which would give us 267.9 in3.
Therefore the answer is the D. 267.9 in3.
I hope this helps!!!
