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siniylev [52]
3 years ago
15

Help please, from anyone.

Mathematics
1 answer:
Fed [463]3 years ago
5 0

Answer:

your answer should be 15%

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justin is redoing his bathroom floor with tiles measuring 6 in. by 13 in. the floor has an area of 8,500 in2. what is the least
Softa [21]


Frist you do 6*13

Which equals 78

Then you do 8,500/78

Which equals <span>108.974358974</span>

<span>Then you round it to 109</span>

<span>and there's your awnser</span>

<span>
</span>

3 0
3 years ago
Read 2 more answers
How to solve -8+squre root (5a-5)=-3
sertanlavr [38]

Answer:

a=6

Step-by-step explanation:

Given equation:

-8+\sqrt{5a-5}=-3

Solving for unknown variable a

Adding 8 both sides by additive property of equality.

+8-8+\sqrt{5a-5}=-3+8

\sqrt{5a-5}=5

Squaring both sides to remove the square root.

(\sqrt{5a-5})^2=5^2

5a-5=25

Adding 5 both sides by additive property of equality.

5a-5+5=25+5

5a=30

Dividing both sides by 6 to isolate a

\frac{5a}{5}=\frac{30}{5}

∴ a=6

8 0
3 years ago
kai pixked 11 times as many blueberries as nico. . together they picked 936. hiw many blueberries did each boy pick?
Masja [62]
N = how many blueberries Nico picked
11n = how many blueberries Kai picked

11n + n = 936
12n = 936
n = 78

11 (78) = 858 blueberries

Nico picked 78 and Kai picked 858
4 0
3 years ago
What is area of this
nata0808 [166]

Answer:

A = 20.5 sq units

Step-by-step explanation:

you have the height of 5 but need to figure out the base

we can use the Pythagorean Theorem two times to find it

1) a² + 5² = 7²

a² = 49-25

a = \sqrt{24} = \sqrt{4}·\sqrt{6} = 2\sqrt{6}

2) b² + 5² = 6²

b² = 36-25

b = \sqrt{11}

Base = 2\sqrt{6} + \sqrt{11}

A = 1/2 x 5· (2\sqrt{6} + \sqrt{11})

A = 2.5 · (2\sqrt{6} + \sqrt{11})

A = 2.5(8.2)

A = 20.5

3 0
3 years ago
Find the coordinates of the midpoint of the segment given its endpoints.
Vesna [10]

Answer:

(2, 2 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

[ \frac{1}{2} (x₁ + x₂ ) , \frac{1}{2} (y₁ + y₂ ) ]

Here (x₁, y₁ ) = (A(5, 8) and (x₂, y₂ ) = B(- 1, - 4) , thus

midpoint = [ \frac{1}{2} (5 - 1), \frac{1}{2} (8 - 4 ) ] = (2, 2 )

6 0
3 years ago
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