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3 years ago

15

PLEASE HELP!!!!Math Homework

1 answer:

Finger [1]3 years ago

8 0

You need to add the second number and the answer to get your answer

A. 2

B.6

D.5

F.4

G. 3

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3 years ago

Read 2 more answers

The population of a town increased from 3,250 in 2008 to 4,300 in 2010. Find the absolute and relative(percent) increase.

Umnica [9.8K]

Answer:

The absolute difference is 1050

The relative percentage is 32.3076%

Step-by-step explanation:

We are given

The population of a town increased from 3,250 in 2008 to 4,300 in 2010

In 2008:

$P_1=3250$

In 2010:

$P_2=4300$

Absolute difference:

we know that

absolute difference = $P_2-P_1$

absolute difference = $4300-3250$

absolute difference is 1050

Relative increase:

we know that

Relative percentage is

$=\frac{P_2-P_1}{P_1}\times 100$

now, we can plug values

$=\frac{1050}{3250}\times 100$

=32.3076

So, the relative percentage is 32.3076%

3 0

3 years ago

I need help on these problems help???

Korvikt [17]

Use PEMDAS.

P = Parentheses

E = Exponent

M = Multiplication

D = Division

A = Addition

S = Subtraction

This is the order of operations.

For example, let's take the second equation.

36 / 6 + 10 * 66

There are no parentheses or exponents.

So, first we multiply.

36 / 6 + 660

Then we divide.

6 + 660

Then we add.

666

So the equation equals 666.

6 0

3 years ago