3 years ago

Question 7

Mathematics

1 answer:

Elina [12.6K]3 years ago

5 0

D is right because there is not tire

You might be interested in

Which of these graphs represents a function? A. W В. Х C. Y D. Z

NNADVOKAT [17]

Answer:

its b

Step-by-step explanation:

draw a line down the middle of the figure and if it passes through two points its not a function but if it only goes through one then it is a function.

3 0

4 years ago

Read 2 more answers

One day in January the temperature dropped steadily from 3 degrees to negative 3 degrees. What was the change in temperature?

eduard

The change in temperature is -6 Degrees

6 0

3 years ago

Read 2 more answers

Minimum and maximum of this graph??

shtirl [24]

Hi!

The minimum is the lowest possibility on the graph, and the maximum is the highest.

In this graph, the highest point (the maximum) is (10,11) and the lowest point (the minimum) is (3, 1).

Hope this helps! :D

6 0

3 years ago

Write an equation of a line in slope-intercept from that passes through the given points

Archy [21]

Answer:

y = 4x - 1

Step-by-step explanation:

slope: 7-3/2-1 = 4

y= mx+b

7= 4(2) + b

b= -1

y = 4x - 1

5 0

3 years ago

Read 2 more answers

(1 point) For the equation given below, evaluate ′ at the point (−1,2). (5−)^4+4^3=2433. ′ at (−1,2) =

ryzh [129]

Answer:

$\dfrac{343}{71}$

Step-by-step explanation:

Given the equation

$(5x-y)^4+4y^3=2433$

Find the derivative:

$((5x-y)^4+4y^3)'=(2433)'\\ \\4(5x-y)^3\cdot (5x-y)'+4\cdot 3y^2\cdot y'=0\\ \\4(5x-y)^3\cdot (5-y')+12y^2y'=0$

Substitute

$x=-1\\ \\y=2,$

then

$4(5\cdot (-1)-2)^3\cdot (5-y')+12\cdot 2^2\cdot y'=0\\ \\4(-5-2)^3(5-y')+48y'=0\\ \\4\cdot (-7)^3\cdot (5-y')+48y'=0\\ \\-1,372(5-y')+48y'=0\\ \\-6,860+1,372y'+48y'=0\\ \\1,420y'=6,860\\ \\y'=\dfrac{6,860}{1,420}=\dfrac{686}{142}=\dfrac{343}{71}$

6 0

3 years ago