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2 years ago

Can someone help me with number 7 the circled one?

Mathematics

1 answer:

Ivenika [448]2 years ago

5 0

Your answer:
<span>Equation:
x(x+1) = 2(x+1)+77
-----

x^2+x = 2x+79
x^2-x-79 = 0
------
This quadratic does not have an integer solution.</span>

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How fast is a train going that makes a 330 mile trip in 4 hours.?

maw [93]

Answer:

82.5 miles an hour

330 ÷ 4 = 82.5

Step-by-step explanation:

8 0

3 years ago

You work 4 hours on Monday, 4.5 hours on Tuesday, 7.25 hours on Thursday, and 12 hours on Saturday. If you get paid $11.52 per h

ch4aika [34]

Answer:

$319.43

Step-by-step explanation:

Monday= 4 * $11.52= $46.08

Tuesday= 4.5 * $11.52= $51.84

Thursday= 7.25 * $11.52= $83.27

Saturday= 12 * $11.52= $138.24

When you add all of those together you get $319.43

hope this helped (:

(this took so long so this better be right...<3)

6 0

2 years ago

Mr.Hollis determines that he gives away $800 each month if he gives away 16% of his budget, how much is his overall budget

Fittoniya [83]

His budget is $5000

you take 800 and divide it by 0.16

gives you 5000

4 0

3 years ago

The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78

____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

$m-t_{a/2,n-1}\frac{s}{\sqrt{n} }$ ≤ μ ≤ $m+t_{a/2,n-1}\frac{s}{\sqrt{n} }$

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and $t_{a/2,n-1}$ is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and $t_{0.05,9}$ by 1.8331, we get that the 90% confidence interval for the mean speed is:

$74.2-(1.8331)\frac{5.3083}{\sqrt{10} }$ ≤ μ ≤ $74.2+(1.8331)\frac{5.3083}{\sqrt{10} }$

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0

2 years ago

Pleaseee someone help me in this question ihave bben eating for half an hour and no one helped me.

pav-90 [236]

Cross Multiply by 'x - 5'
Hence
y(x - 5) = 4 -3x
xy - 5y = 4 - 3x

Move all the terms containing an 'x' to one side of the equals and all the others to the opposite side.
xy + 3x = 4 + 5y
Factor out 'x'
x(y + 3) = 4 + 5y
'Cross' divide by 'y + 3'
x = ( 4 + 5y) / (y + 3 )

'x' is now the subject.

8 0

3 years ago