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2 years ago

Carol has 10 cups of sugar to make 7 dozen cookies.if she only had 6 cups of sugar how many cookies could she make.

Mathematics

1 answer:

Inessa [10]2 years ago

3 0

If carol has 10 cups of sugar to make 7 dozen cookies he can make 84 cookies

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110% OF WHAT NUMBER IS 880? SHOW EVERY STEP PLZ:)

Nookie1986 [14]

So 110% of x is 880 means 1.1x=880

so 1.1x=880
multiply both sides by 10
11x=8800
divide both sides by 11
8800=88 times 100 88=8 times 11
8800/11=800
x=800

5 0

3 years ago

Read 2 more answers

Energy for both renewable and nonrenewable sources originally comes from

Korvikt [17]

Answer:

Step-by-step explanation:

the sun is the primary source

6 0

1 year ago

Use square ABCD for this problem IF AC=26,find BC.

katen-ka-za [31]

Answer:

x= $\sqrt{338}$

Step-by-step explanation:

$a^2+b^2=c^2$

$x^2+x^2=$ $26^2$

$2x^2=26^2$

$2x^2=676$

/2 /2

$x^2=338$

$\sqrt{x^2} =\sqrt{338}$

x= $\sqrt{338}$

8 0

3 years ago

Read 2 more answers

The length of a rectangle is 6 inches more than its width. Its area is 91 square inches. The length is .

Vika [28.1K]

Answer:

13 in

Step-by-step explanation:

let w be width then length is w + 6

the area (A) of a rectangle is calculated as

A = length × width , then

A = w(w + 6) = 91 , that is

w² + 6w = 91 ( subtract 91 from both sides )

w² + 6w - 91 = 0 ← in standard quadratic form

(w + 13)(w - 7) = 0 ← in factored form

equate each factor to zero and solve for w

w + 13 = 0 ⇒ w = - 13

w - 7 = 0 ⇒ w = 7

however, w > 0 then w = 7

and length = w + 6 = 7 + 6 = 13 in

8 0

1 year ago

Use Lagrange multipliers to find the volume of the largest rectangular box in the first octant with three faces in the coordinat

tensa zangetsu [6.8K]

Answer:

The volume of the largest rectangular box (V) = 81/4

Step-by-step explanation:

Step 1:-

Given volume of the largest rectangular box in the first octant

V = l b h

let (x ,y, z) be the one vertex in the given plane

V = f(x, y, z) = x y z

given plane. Ф (x, y, z) = x + 9y + 4z = 27 ........(1)

Step( ii):

By using Lagrange multipliers

Suppose it is required to find the extreme for the function f(x, y, z) subject to the condition Ф (x, y, z) =0

Form Lagrange function F(x, y, z) = f(x, y, z) + λ Ф (x, y, z) where λ is called the Lagrange multipliers

F(x, y, z) = x y z+ λ ( x + 9y + 4z - 27) ......(2)

Obtain the equations are δ F / δ x = 0

δ f / δ x +λ δ Ф / δ x =0

⇒ y z + λ ( 1) = 0

⇒ y z = - λ ......(a)

Obtain the equations are δ F / δ y = 0

δ f / δ x +λ δ Ф / δ x =0

⇒ x z + λ ( 9) = 0

⇒ $\frac{xz}{9}$ = - λ .......(b)

Obtain the equations are δ F / δ z = 0

δ f / δ x +λ δ Ф / δ z =0

x y + λ ( 4) = 0

⇒ $\frac{xy}{4}$ = - λ .......(c)

Step (iii):-

Equating (a) and (b) equations

we get $y z = \frac{xz}{9}$

cancel 'z' value we get x = 9y .......(d)

Equating (b) and (c) equations

we get $\frac{xy}{4} = \frac{xz}{9}$

cancel 'x' value on both sides , we get

4z =9y ......(e)

substitute (d) (e) values in equation (1) we get

x + 9y + 4z -27 = 0

9y + 9y + 9y -27 =0

27y -27 =0

y = 1

substitute y =1 in x = 9y

x = 9

substitute y =1 in 4z =9y

z = 9 /4

therefore the dimensions are x =9 , y=1 and z = 9 /4

Conclusion:-

The largest volume of the rectangular box V = x y z

substitute x =9 , y=1 and z = 9 /4

V = 9(1)(9/4) =81/4

The largest volume of the rectangular box (V) = 81/4

Verification :-

Given plane x + 9y + 4z = 27

substitute x =9 , y=1 and z = 9 /4

9 + 9 + 4(9/4) = 27

27 =27

so satisfied equation

3 0

3 years ago