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2 years ago

11 th term of the following geometric sequence. 10,50,250,1250

Mathematics

1 answer:

Natasha2012 [34]2 years ago

6 0

Answer:

97,656,250

Step-by-step explanation:

The first term, a(1), is 10. The next is 5 times greater. And so on. Thus, the common ratio is 5, and the general formula for this sequence is

a(n) = a(1)*5^(n -1).

Therefore,

a(11) = 10*5^(11 - 1) = 10*5^10 = 97,656,250

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iogann1982 [59]

$\bf =ae^{kt}\qquad 
\begin{cases}
1994\impliedby \textit{year 0, starting point}\\
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\end{cases}\implies 182=ae^{k0}
\\\\\\
182=a\cdot e^0\implies 182=a\cdot 1\implies 182=a
\\\\\\
thus\qquad P=182e^{kt}\\\\
-------------------------------\\\\$

$\bf P=182e^{kt}\qquad 
\begin{cases}
2002\impliedby \textit{8 years later}\\
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\\\\\\
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\\\\\\
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