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3 years ago

How are <8 and <4 related

Mathematics

1 answer:

Tasya [4]3 years ago

3 0

Answer:

8 divided by 2 is 4

Step-by-step explanation:

U divide 8 from 2

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SOMEONE EASE ANSWER NUMBER 4?

nlexa [21]

On analyzing the question we can say that the angle ∠JKM of the triangle ΔJKL would be 42 as line MK bisects ∠JKL into ∠JKM & ∠MKL.

From the question it follows that line MK bisects angle ∠JKL into ∠JKM & ∠MKL where M is the point in the interior of ∠JKL.

Therefore, as we have given m∠JKL = 84 & m∠MKL = 42

and we have to find m∠JKM , we will simply write the equation as follow

m∠JKL = m∠JKM + m∠MKL

Inserting values we get,

84 = m∠JKM + 42

m∠JKM = 42

Hence, angle m∠JKM of the triangle ΔJKL is 42.

Learn more about questions related to triangles and their angles here

brainly.com/question/13273388

#SPJ9

5 0

1 year ago

Help with both questions offering 10 points

Alexandra [31]

Answer:

$\:\mathrm{First\: problem:\:}-2,\\\:\mathrm{Second\: problem:\: }-3$

Step-by-step explanation:

The slope of a line passing through points $(x_1, y_1)$ and $(x_2, y_2)$ is:

$m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}$

Plugging in any two points in the table we have:

First problem:

$m=\frac{1-5}{2-0}=\frac{-4}{2}=\fbox{$-2$}$

Second problem:

$m=\frac{-1-5}{2-0}=\frac{-6}{2}=\fbox{$-3$}$

8 0

3 years ago

Read 2 more answers

A supermarket had bags of red apples for $27.09 for 7. The also had bags of green apples priced at $14.96 for 4. Which type of a

jarptica [38.1K]

Answer:

Red

Step-by-step explanation:

RED:

$27.09 / 7 = $3.87

GREEN:

$14.96 / 4 = $3.74

$3.87 > $3.74

7 0

2 years ago

1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING

iogann1982 [59]

$y=\displaystyle\sum_{n=0}^\infty a_nx^n$

then

$y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n$

The ODE in terms of these series is

$\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0$

$\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0$

$\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}$

We can solve the recurrence exactly by substitution:

$a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0$

$\implies a_n=\dfrac{(-2)^n}{n!}a_0$

So the ODE has solution

$y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}$

which you may recognize as the power series of the exponential function. Then

$\boxed{y(x)=a_0e^{-2x}}$

7 0

3 years ago

Which type of transformation could cause a change in the period of a tangent or cotangent function? vertical shift phase shift v

siniylev [52]

The horizontal stretch is the correct answer. A period is the distance on the x-axis that it takes for the tangent or cotangent function to repeat itself. Stretching it out horizontally will lengthen that distance and therefore change the period.

7 0

3 years ago

Read 2 more answers