Factors of 18: 1; 2; 3; 6; 9; 18
Factors of 27: 1; 3; 9; 27
GCF(18; 27) = 9
<span>18 + 27 = 9 × 2 + 9 × 3 = 9 × (2 + 3) </span>
Answer:
<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>
Step-by-step explanation:
Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:
<h3>To find how many imaginary roots does the polynomial have :</h3>
- Since the degree of given polynomial is 4
- Therefore it must have four roots.
- Already given that the given polynomial has 1 positive real root and 1 negative real root .
- Every polynomial with degree greater than 1 has atleast one imaginary root.
<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>
I found the awnser by doing 10x10x2 witch equals 200. Then i know that 10x9 equals 90 so, you would get 29 dimes.
Answer:
i think it would be 10,000
I hope it helped!
Answer:
-35.5
Step-by-step explanation:
