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3 years ago

Please some urgent help!!!!

Mathematics

2 answers:

Elden [556K]3 years ago

5 0

Answer:

brain less or i hack ur acc to ban

Step-by-step explanation:

u cant report me because im hacker

Viktor [21]3 years ago

3 0

The anwser would be 2.
This is because of the blue line in the middle so you only have to count one half

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How do letter represent number

Brilliant_brown [7]

1 is M
2 is I
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9 is H

The thing at the bottom is
ARITHMATICKS

7 0

3 years ago

4(-3x-5)-(10+4x) simplify

bixtya [17]

Answer:

-16x - 30

Step-by-step explanation:

4(-3x - 5) - (10 + 4x) = 4*(-3x) - 4*5 + (-1)*10 + (-1)*4x

= -12x - 20 - 10 - 4x {add like terms}

= -12x - 4x - 20 - 10

= -16x - 30

7 0

4 years ago

Read 2 more answers

Can anyone please help me solve for x? Thank you!

Amiraneli [1.4K]

X= (k+c):(m- ny/b)=(k+c): (mb-ny)/b= (k+c)*b/(mb-ny)
x= (bc+bk)/bm-ny

D is correct

5 0

3 years ago

Read 2 more answers

A data set includes 103103 body temperatures of healthy adult humans having a mean of 98.998.9degrees°f and a standard deviation

dangina [55]

Answer:

$98.9-2.62\frac{0.65}{\sqrt{103}}=98.73$

$98.9+2.62\frac{0.65}{\sqrt{103}}=99.07$

So on this case the 99% confidence interval would be given by (98.73;99.07)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=98.9$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=0.65 represent the sample standard deviation

n=103 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=103-1=102$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,102)".And we see that $t_{\alpha/2}=2.62$