A line segment from a vertex to the midpoint of the opposite side is a "median". A median divides the area of the triangle in half, as it divides the base in half without changing the altitude.
AAMC is half AABC. AADC is half AAMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
ABMC is half AABC. ABMD is half ABMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
Then, AADC = 1/4 AABC = ABMC, so AADC = ABMC by the transitive property of equality.
Answer:
C. 15²π
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Geometry</u>
- Diameter: d = 2r
- Area of a Circle: A = πr²
Step-by-step explanation:
<u>Step 1: Define</u>
d = 30 m
<u>Step 2: Find Area</u>
- Substitute [D]: 30 m = 2r
- Isolate <em>r</em>: 15 m = r
- Rewrite: r = 15 m
- Substitute [AC]: A = π(15 m)²
- Rearrange: A = 15²π
The bottom answer m y = m h