Answer:
10 and 6
Step-by-step explanation:
Let A be the area of the rectangle, w the width and L the length
● A = w*L
The length is 4 feet more that the width so L = w+4
● A = w ×(w+4)
● A = w^2 + 4w
The area is 60 ft^2
● w^2 + 4w = 60
Substract 60 from both sides
● w^2 + 4w - 60 = 0
This a quadratic equation
We will solve it by graphing it
The solution are 6 and -10 since the graph intersect with the x-axis in those points (pictures below)
The width is 6 feet long since it is a distance and a distance is always positive.
● w = 6
● L = w + 4
● L = 6 + 4
● L = 10
The width is 6 feet and the length is 10 feet
Answer:
y = 4
Step-by-step explanation:
y - 1 = √y + 5
(y - 1)² = y + 5 (Square both sides)
y² - 2y + 1 = y + 5 (Expand left side)
y² - 3y - 4 = 0 (Subtract y and 5 from both sides)
(y + 1) (y - 4) = 0 (Factor)
y = -1, 4 (Use ZPP)
When we check y = -1 we see that it is not a solution so the answer is y = 4.
2= f/8
F is being divided by eight , when moving across equal sign the sign is opposite.
2 x 8 = f
16=f
Tangent 45 = height / 3
height = 3 * tan (45)
height = 3 * 1
height = 3
<span>Trapezoid area = ((sum of the bases) ÷ 2) • height
</span>
<span>Trapezoid area = (9 + 15) /2 * height
</span><span>Trapezoid area = 12 * 3
</span><span>Trapezoid area = 36
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