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3 years ago

Please I need an answer quick

Mathematics

1 answer:

lubasha [3.4K]3 years ago

5 0

Answer:

What's the problem

Step-by-step explanation:

20 characters

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I have to put spaces so delete the spaces ok

loris [4]

Answer:

wdym???

Step-by-step explanation:

You have an email with at white buffalos.net??? I thought that was only my school.

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3 years ago

Fill in the blank. Using the number line below, the plotted number is when rounded to the nearest thousand.

prisoha [69]

Answer:

5000

Step-by-step explanation:

if its 5 or more round up. If it's 4 or less round down

6 0

2 years ago

The cost of oranges varies directly as the number of oranges sold. If 8 oranges cost $10.40, how many oranges can be bought for

alexdok [17]

Answer:

Step-by-step explanation:

if you can get 8 oranges for 10.40 then divide 10.40 by 8. you can get each orange for 1.3. you need to know how many oranges you can get for 33.8 so divide that by 1.3 and you get 26

6 0

2 years ago

Read 2 more answers

What is the area of the partial circle with a radius of 8 cm? Use 3. 14 for pi.

Olegator [25]

Radius=r=8cm

$\\ \tt\hookrightarrow Area=\pi r^2$

$\\ \tt\hookrightarrow Area=\pi 8^2$

$\\ \tt\hookrightarrow Area=64\pi$

$\\ \tt\hookrightarrow Area=64(3.14)$

$\\ \tt\hookrightarrow Area=200.96cm^2$

8 0

2 years ago

Read 2 more answers

Factor the polynomial function over the complex numbers. f(x)=x^4-x^3-2x−4 Enter your answer in the box. f(x) = The answer is: (

Vladimir79 [104]

Answer:

Factors: $(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0$

Step-by-step explanation:

We are given a polynomial:

$f(x)=x^4-x^3-2x-4$

We have to factor the given polynomial into its complex factors.

The factorization can be done as follows:

$f(x)=x^4-x^3-2x-4 = 0\\x^4-x^3-2x-4 = 0\\x^4-4-x^3-2x=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^4-4)-(x^3+2x) = 0\\(x^2+2)(x^2-2)-x(x^2+2) = 0\\(x^2+2)(x^2-2-x) = 0\\(x^2+2)(x^2-x-2) = 0\\(x^2+2)(x^2-2x-+x-2) = 0\\(x^2+2)((x(x-2)+1(x-2))=0\\(x^2+2)(x+1)(x-2)=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^2-(\sqrt{-2})^2)(x+1)(x-2)=0\\(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0$

8 0

2 years ago