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Alexandra [31]
3 years ago
10

6x+y=4x+11y find the formula

Mathematics
1 answer:
atroni [7]3 years ago
7 0

Answer:

x=5y Hope this helped.

Step-by-step explanation:

6x+y=4x+11y

Step 1: Add -4x to both sides.

6x+y+−4x=4x+11y+−4x

2x+y=11y

Step 2: Add -y to both sides.

2x+y+−y=11y+−y

2x=10y

Step 3: Divide both sides by 2.

2x

2

=

10y

2

x=5y

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Point V is on line segment UW. Given UW=13 and VW = 11, determine the length of UV
jekas [21]

Answer:

UV = 2

Step-by-step explanation:

Given

UW = 13

VW = 11

Required

Determine UV

From the question, we have

UW = UV + VW

Make UV the subject of formula

UV = UW - VW

Substitute 11 and 13 for VW and UW, respectively

UV = 13 - 11

UV = 2

8 0
3 years ago
What is bigger 6 kg or 600 g
Alexeev081 [22]

Answer:

6kg

Step-by-step explanation:

kg are bigger than g

7 0
2 years ago
Read 2 more answers
According to data from the state blood program, 40 percent of all individuals have group A blood. If six individuals give blood,
Serjik [45]

Answer: 0.27648

Step-by-step explanation:

Given : The proportion of all  individuals have group A blood : p=0.040

Total individuals give blood : n= 6

Let X be the number of individuals have group A blood.

Since all individual are independent of each other.

X\sim Bin(n=6, p=0.40)

Formula : P(X=x)=^nC_xp^x(1-p)^{n-x} , where n= sample size , p = probability of getting success in each trial.

The probability that exactly three of the individuals have group A blood. :

P(x=3)= ^6C_3(0.40)^3(1-0.4)^3\\\\= \dfrac{6!}{3!3!}\times(0.40)^3(0.60)^3\\\\=0.27648

The probability that exactly three of the individuals have group A blood. is 0.27648

8 0
3 years ago
Write parametric equations of the line through the points (7,1,-5) and (3,4,-2). please use the first point as your base-point w
Roman55 [17]

Given:

A line through the points (7,1,-5) and (3,4,-2).

To find:

The parametric equations of the line.

Solution:

Direction vector for the points (7,1,-5) and (3,4,-2) is

\vec {v}=\left

\vec {v}=\left

\vec {v}=\left

Now, the perimetric equations for initial point (x_0,y_0,z_0) with direction vector \vec{v}=\left, are

x=x_0+at

y=y_0+bt

z=z_0+ct

The initial point is (7,1,-5) and direction vector is \vec {v}=\left. So the perimetric equations are

x=(7)+(-4)t

x=7-4t

Similarly,

y=1+3t

z=-5+3t

Therefore, the required perimetric equations are x=7-4t, y=1+3t and z=-5+3t.

5 0
3 years ago
What is the sum of the first 70 consecutive odd numbers? Explain.
expeople1 [14]

The sum of the first n odd numbers is n squared! So, the short answer is that the sum of the first 70 odd numbers is 70 squared, i.e. 4900.

Allow me to prove the result: odd numbers come in the form 2n-1, because 2n is always even, and the number immediately before an even number is always odd.

So, if we sum the first N odd numbers, we have

\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1

The first sum is the sum of all integers from 1 to N, which is N(N+1)/2. We want twice this sum, so we have

\displaystyle 2\sum_{i=1}^N i = 2\cdot\dfrac{N(N+1)}{2}=N(N+1)

The second sum is simply the sum of N ones:

\underbrace{1+1+1\ldots+1}_{N\text{ times}}=N

So, the final result is

\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1 = N(N+1)-N = N^2+N-N = N^2

which ends the proof.

5 0
2 years ago
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