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3 years ago

I can't find the right answer

Mathematics

2 answers:

ZanzabumX [31]3 years ago

8 0

Answer:

You can take the square root of the inequality x^2<4, which will make it x< plus or minus 2 (x<2, x<-2)

You know it is this answer because, the sign cannot be greater than or equal to since the circles aren't filled, and if you solve the other inequality, the answer you get does not match.

Hope this helps!! :)

Alik [6]3 years ago

7 0

Answer:

x^2 ≥ 4

Step-by-step explanation:

$x^2\ge \:4\\\\\mathrm{For\:}u^n\:\ge \:\:a\\\mathrm{,\:if\:}n\:\mathrm{is\:even}\mathrm{\:then\:}u\:\le \:\:-\sqrt[n]{a}\:or\:u\:\ge \sqrt[n]{a}\\\\x\le \:-\sqrt{4}\quad \mathrm{or}\quad \:x\ge \sqrt{4}\\\\\sqrt{4}=2\\\\x\le \:-2\quad \mathrm{or}\quad \:x\ge \:2$

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3 years ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y

lubasha [3.4K]

First find a parameterization for the curve of intersection.

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which suggests we could use

$\begin{cases}x(t)=\cos t\\y(t)=4\sin t\\z(t)\end{cases}$

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$\displaystyle\ell=\int_0^{2\pi}\sqrt{\left(\dfrac{\mathrm dx}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dy}{\mathrm dt}\right)^2+\left(\dfrac{\mathrm dz}{\mathrm dt}\right)^2}\,\mathrm dt$

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Area of right-angled triangle is given by;

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Therefore,

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Ratio of increase = A2/A1 = {2bh}/(1/2bh} = 4 (the area is increased 4 times)
The,
A2 = 4*16 = 64 in^2
Therefore,
The area is increased by (64-16) = 48 in^2

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Answer:

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