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nikdorinn [45]
4 years ago
7

What does the grid represent

Mathematics
2 answers:
konstantin123 [22]4 years ago
4 0

Answer:

0.030

Step-by-step explanation:

I don't really know how to explain this one, sorry.

Hope this helps! (✿◕‿◕✿)

Scrat [10]4 years ago
3 0

\tt Step-by-step~explanation:

We have to find out what the shaded regions represent. We can count up ten rectangles in total, and three of them are shaded. We take the amount of shaded rectangles over the total amount to get \tt \frac{3}{10} as a fraction, and 0.3 as a decimal.

\tt First~option:

The first choice is 0.300. The zeroes at the end of the number do not mean anything, so we can simplify it to 0.3. 0.3 is equal to 0.3, so this is not the answer.

\tt Second~ option:

The second choice is 0.30. Again, we can simplify it to 0.3. We can see that it is equivalent to 0.3, so this is not the answer, either.

\tt Third~option:

Our third choice is 0.3. 0.3 = 0.3, so this is not our answer either.

\tt Fourth ~option:

Our final choice is 0.030. Take out the last zero to get 0.03. 0.03 is equal to \tt \frac{3}{100}, so this is our answer, since it is not 0.3.

\large\boxed{\tt Our ~final~answer:~Last~option:~0.030}

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3 years ago
Which of the following is an arithmetic sequence
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Answer:

A sequence that has a contant addition/subtraction to get to the next term

for example:

-3, 0, 3, 6, ...

to get to the next term, we'll need to add 3 each time

Step-by-step explanation:

3 0
3 years ago
Classify each differential equation as separable, exact, linear, homogeneous, or Bernoulli. Some equations may be more than one
sergey [27]

Answer:

a) dy/dx = (x − y)/x. This is exact, linear in y, and homogeneous.

b) (x + 1)dy/dx = −y + 20. This is separable, exact, and liner in x and y.

c) dy/dx = 1/(x(x − y2)). This is Bernoulli in x.

d) dy/dx =(y^2 + y)/(x^2 + x). This is Bernoulli in x and y, and Separable.

e) dy/dx = 5y + y^2. This is Bernoulli in y, and Separable.

f) y dx = (y − xy^2) dy. This is linear in x.

g) x dy/dx = ye^(xy) – x. This is homogeneous.

h) 2xyy' + y^2 = 2x^2. This is exact, homogeneous, and Bernoulli.

i) y dx + x dy = 0. This is exact, homogeneous, separable, and linear in x and y.

k) (x^2 + 2y/x) dx = (3 − ln x^2) dy. This is exact, and linear in y.

l) (y/x^2) dy/dx + e^(2x^3) + y^2 = 0. This is separable.

Step-by-step explanation:

The following categories of each of the differential equation are first explained as follows:

Separable differential equation: Any equation that can be expressed in the form y′=f(x)g is a separable differential equation (y).

Exact differential equation: This is a type of differential equation that can be solved directly without the use of any of the special techniques in the subject.

Linear differential equation: This is a form of differential equation that can be solved without resorting to any of the subject's unique techniques.

Homogeneous differential equation: A differential equation is said to be homogeneous if it is a homogeneous function of the unknown function and its derivatives.

Bernoulli differential equation: If an ordinary differential equation has the form y' + P(x)y = Q(x)y^n, where n is a real number, it is referred to as a Bernoulli differential equation.

Since the question indicates "Do not solve", we therefore only classify as follows:

a) dy/dx = (x − y)/x. This is exact, linear in y, and homogeneous.

b) (x + 1)dy/dx = −y + 20. This is separable, exact, and liner in x and y.

c) dy/dx = 1/(x(x − y2)). This is Bernoulli in x.

d) dy/dx =(y^2 + y)/(x^2 + x). This is Bernoulli in x and y, and Separable.

e) dy/dx = 5y + y^2. This is Bernoulli in y, and Separable.

f) y dx = (y − xy^2) dy. This is linear in x.

g) x dy/dx = ye^(xy) – x. This is homogeneous.

h) 2xyy' + y^2 = 2x^2. This is exact, homogeneous, and Bernoulli.

i) y dx + x dy = 0. This is exact, homogeneous, separable, and linear in x and y.

k) (x^2 + 2y/x) dx = (3 − ln x^2) dy. This is exact, and linear in y.

l) (y/x^2) dy/dx + e^(2x^3) + y^2 = 0. This is separable.

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4 years ago
Y=2x
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this is the answer hope it helps you

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