Answer:
(a) The value of <em>x</em> is 0.30.
(b) The probability that a reported case of rabies is not a raccoon is 0.45.
(c) The probability that a reported case of rabies is either a bat or a fox is 0.15.
Step-by-step explanation:
Denote the events as follows:
<em>R</em> = reported case of rabies is a raccoon
<em>F</em> = reported case of rabies is a fox
<em>B</em> = reported case of rabies is a bat
<em>O</em> = reported case of rabies is a some other animal.
The data provided is:
P (R) = 0.55
P (F) = 0.11
P (B) = 0.04
P (O) = <em>x</em>.
(a)
A property of a probability distribution is that the sum of all individual properties is 1.
That is, 
Compute the value of <em>x</em> as follows:

Thus, the value of <em>x</em> is 0.30.
(b)
The probability of the complement of an event is the probability of its not happening.

Compute the probability that a reported case of rabies is not a raccoon as follows:

Thus, the probability that a reported case of rabies is not a raccoon is 0.45.
(c)
Compute the probability that a reported case of rabies is either a bat or a fox as follows:

Thus, the probability that a reported case of rabies is either a bat or a fox is 0.15.