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lesya692 [45]
3 years ago
8

Working alone, Ryan can dig a 10 ft by 10 ft hole in five hours. Castel can dig the same hole in six hours. How long would it ta

ke them if they worked together?
Mathematics
1 answer:
Neporo4naja [7]3 years ago
5 0

Answer:

it would take 3 to 4 hours

Step-by-step explanation:

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Mai biked 7 and 1/4 miles today, and Noah biked 3 5/8 miles. How many times the length of Noah's bike ride was Mai's bike ride?
Firdavs [7]

Answer:

2 times

Step-by-step explanation:

Mai biked 7\frac{1}{4} = \frac{29}{4} miles today and Noah biked 3\frac{5}{8} = \frac{29}{8} miles  today.

We are asked how many times the length of Noah's bike ride was Mai's bike ride.

Therefore, the length of Mai's bike ride was (\frac{29}{4} \div \frac{29}{8})  = 2 times the length of Noah's bike ride.  

Therefore, we will take option B will be correct. ( Answer )

7 0
3 years ago
M% of n is what percent of p?<br> FIND FOR PERCENT
makvit [3.9K]

Answer:

m*p/n = percent

Step-by-step explanation:

m% of n is what percent of p?

We can use ratios

m             percent

------- =  ---------------

n                    p

Using cross products

m*p = n * percent

Divide each side by n

m*p/n = percent

5 0
3 years ago
Show that the relation R consisting of all pairs(x, y)such that x and y are bit strings of length three or more that agree in th
Mice21 [21]

Answer:

See proof below

Step-by-step explanation:

An equivalence relation R satisfies

  • Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
  • Symmetry: For all x,y, if xRy then yRx.
  • Transitivity: For all x,y,z, If xRy and yRz then xRz.

Let's check these properties: Let x,y,z be bit strings of length three or more

The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.

If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.

If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.

5 0
3 years ago
Solve for the following equation. 7=r^1/2 please help
Andreas93 [3]
7 = r^1/2 is the same as saying 7 = square root of r. So, to get rid of the square root sign on the r, you need to square it, and when you do something to one side of the equation, you have to do the same to the other side. So after squaring both sides, you get 49 = r.
6 0
3 years ago
Please I need help fast!!!
algol [13]
I’m almost positive it’s C
5 0
3 years ago
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