Answer:
x=12, DO=45O, G=45, DG=90
Step-by-step explanation:
Mid point means both lenghts are equal
4x-3=2x+21
2x=24
X=12
-----------------
1)4(12)-3=48-3=45
2)2(12)+21=24+21=45
-----------------------------
DO=45
OG=45
DG=90
![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](https://tex.z-dn.net/?f=y%3Dx%5E5-3%5C%5C%20y%27%3D5x%5E4%5C%5C%5C%5C%205x%5E4%3D0%5C%5C%20x%3D0%5C%5C%200%5Cin%20%5B-2%2C1%5D%5C%5C%5C%5C%20y%27%27%3D20x%5E3%5C%5C%5C%5C%0Ay%27%27%280%29%3D20%5Ccdot0%5E3%3D0)
The value of the second derivative for

is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of

is always positive for

. That means at

there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval
![[-2,1]](https://tex.z-dn.net/?f=%5B-2%2C1%5D)
.
The function

is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
Given:
angle ECB=51 degrees
=>
angle EOB = 2*angle ECB = 2*51 = 102 degrees = arc EAB
Also given minor arc AB = 72 degrees
therefore
minor arc EA = 102-72=30 degrees