<span>The simplest method to do this is with the vector dot
product. Let the vector A = <9i + 5j> with magnitude √106 be the base
diagonal, and B = <5j + 3k> be the diagonal vector on the side, with
magnitude √34. Then cos θ = (A dot B) divided by the product of the magnitudes.
A dot B =30, so
cos θ = 30 / √(34 x 106)</span>
<span> = 0.4997 ==></span>
<span> θ = 49.19° is the
answer</span>
Answer:
160 (not sure)
Step-by-step explanation:
400 / 2.5 = 160
160x1 = 160
