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liraira [26]
4 years ago
11

Solve q+13-2(q-22)>0 Show all Steps!

Mathematics
1 answer:
Contact [7]4 years ago
8 0
Q+13-2q+44>0
-q+57>0
multiply both sides by -1
q-57>0
q>57
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Solve the system of equations.<br> 2y+7x=−5<br> 5y−7x=12<br> ​
3241004551 [841]

We can solve this by substitution method.

Look at the second equation. If we rearrange to find 7x, we can substitute in the value into the first equation.

5y-7x=12

5y-7x-12=0

5y-12=7x

Therefore, 7x=5y-12

Now replace the 7x in the first equation with 5y - 12:

2y+7x=-5 (substitute in 7x = 5y - 12)

2y+(5y-12)=-5

7y-12=-5

7y=7

y=1

Now that we know y, we can find x by substituting in y = 1 into any equation we want. I will use the equation: 7x = 5y - 12

7x=5y-12 (substitute in y = 1)

7x=5(1) -12

5x=5-12

7x=-7

x=-1

__________________________________________________________

<u>Answer:</u>

<u></u>y=1\\x=-1<u></u>

4 0
3 years ago
A graph titled Cost of a Lunch in a School's Cafeteria has Days since school started on the x-axis and cost of lunch (dollars) o
Rufina [12.5K]

The true statement about the graph's slope is (c) Its slope is zero.

<h3>How to determine the true statement?</h3>

From the question, we have:

A horizontal line is at y = 2.5.

The horizontal line implies that the cost of lunch do not change

Horizontal lines have a slope of 0

Hence, the true statement about the graph's slope is (c) Its slope is zero.

Read more about slope at:

brainly.com/question/3493733

#SPJ1

8 0
2 years ago
You use a line of best fit for a set of data to make a prediction about an unknown value. the correlation coeffecient is -0.833
alina1380 [7]

Answer: The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2  = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.

Step-by-step explanation: this is the same paragraph The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2  = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.

5 0
3 years ago
Answer 3-4 pleaseeeeee
aivan3 [116]
I think #4 is 4 but I'm not completely sure
4 0
4 years ago
Find a cubic function that has the roots 5 and 3-2i
Zolol [24]

Answer:

P(x)=x^3-11x^2+43x-65

Step-by-step explanation:

If the complex number 3-2i is a root of a cubic function, then the complex number 3+2i is a root too. Thus, the cubic function has three known roots 5,\ 3-2i,\ 3+2i and can be written as

P(x)=(x-5)(x-(3-2i))(x-(3+2i)),\\ \\P(x)=(x-5)(x^2-x(3-2i+3+2i)+(3-2i)(3+2i)),\\ \\P(x)=(x-5)(x^2-6x+9-4i^2),\\ \\P(x)=(x-5)(x^2-6x+9+4),\\ \\P(x)=(x-5)(x^2-6x+13),\\ \\P(x)=x^3-11x^2+43x-65.


4 0
3 years ago
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