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Fantom [35]
3 years ago
7

How long would it take a car with a top speed of 203 mph to travel 2.67 miles up a slope of 6.4% accelerating at 0.092 G's

Mathematics
2 answers:
ahrayia [7]3 years ago
5 0

Answer:

First you would have to multiply and divide the miles driven or travel with acceleration. Than you get 3 minutes and 41 second.

Step-by-step explanation:

melisa1 [442]3 years ago
4 0

Answer:

319.355 seconds.

Step-by-step explanation:

Ok, let us start by writting the parameters given in the question out. First is top speed,V of 203 mph which is equal to 297 feet per seconds(ft/s), the distance of 2.67 miles, the slope Percentage is 6.4 percent, that is, 6.4/100 = 0.064, and the acceleration is at 0.092 g, that is; 3 feet per seconds square(ft/s^2).

Step one: find the angle at which the slope is formed, that is;

tan θ= 0.064.

Therefore, θ= inverse of tan, tan^-1(0.064) = 3.7°.

Step two: calculate the net acceleration; this can be calculated using the formula below;

Net acceleration,a= acceleration given in the question,a(1) - (g×sin θ).

Hence, net acceleration,a= 3 - (sin 3.7° × 32).

====> a= 3- 2.1= 0.93 ft/s^2.

Step three: calculate the time taken to cover the distance. This can be calculated by using the formula below;

Top Speed,v= initial velocity, u + (acceleration,a × time taken, t).

The initial velocity is zero, therefore, v=at.

Time taken, t= v/a.

Time taken= 297/0.93.

Time taken, t= 319.355 seconds.

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Answer:

The answer is option 3.

Step-by-step explanation:

Option 3 is correct because it has parentheses around 40 - x, but not the cube itself or the 3rd power if you didn't know what I meant. Anyway, the reason this is correct is because if you look at any order of operations, you will notice that parentheses always comes before powered numbers, so if you were to choose, say option 2, it would be a completely different answer than option 3, not to mention wrong also.

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Vaimiti walks at a constant pace of 1.1 m/s and takes 25 minutes to get to school.
Temka [501]

Solution:

<u>Note that:</u>

  • Speed = Distance/Time
  • Vaimiti speed = 1.1 m/s
  • Jabril speed = 1.3 m/s

<u>Converting the time (minutes to seconds) for Vaimiti to reach school:</u>

  • Vaimiti's time to reach school: 25 minutes = 25 x 60 seconds
  • => Vaimiti's time to reach school: 1500 seconds

<u>Converting the time (minutes to seconds) for Jabril to reach school:</u>

  • Jabril's time to reach school: 30 minutes = 30 x 60 seconds
  • => Jabril's time to reach school: 1800 seconds

<u>Finding the distance of Vaimiti:</u>

  • Speed = Distance/Time

Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>

  • => 1.1 meters/second = Distance/1500
  • => 1.1 x 1500 = Distance
  • => 1650 meters = Distance (In meters)

<u>Finding the distance of Jabril:</u>

  • Speed = Distance/Time

Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>

  • 1.3 meters/second = Distance (In meters)/1800 seconds
  • => 1.3 x 1800 = Distance (In meters)
  • => 2340 meters = Distance (In meters)

This can lead to two possible solutions:

Possible solution #1:

<u>Finding the difference between the two distances:</u>

  • 2340 meters - 1650 meters = Difference (In meters)
  • => 690 meters

Possible solution #2:

The difference between the <u>distances they walked</u> is that Jabril walked <u>faster</u> than Vaimiti, but Vaimiti reached <u>school</u> earlier than Jabril because the <u>walking distance</u> for Vaimiti is less than the <u>walking</u> <u>distance</u> for Jabril.

Hoped this helped!

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Answer:

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Step-by-step explanation:

the whole parallelograph is 5 times 10 which equals 50. Devide that by 2 and you get 25

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miskamm [114]
1/9   =   1.11
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           -------
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or....
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29/8  >>>  261/72     (72 is the common denominator)  (Multiply the N and D by 9)
                 -------------
                 269/72

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