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Fantom [35]
3 years ago
7

How long would it take a car with a top speed of 203 mph to travel 2.67 miles up a slope of 6.4% accelerating at 0.092 G's

Mathematics
2 answers:
ahrayia [7]3 years ago
5 0

Answer:

First you would have to multiply and divide the miles driven or travel with acceleration. Than you get 3 minutes and 41 second.

Step-by-step explanation:

melisa1 [442]3 years ago
4 0

Answer:

319.355 seconds.

Step-by-step explanation:

Ok, let us start by writting the parameters given in the question out. First is top speed,V of 203 mph which is equal to 297 feet per seconds(ft/s), the distance of 2.67 miles, the slope Percentage is 6.4 percent, that is, 6.4/100 = 0.064, and the acceleration is at 0.092 g, that is; 3 feet per seconds square(ft/s^2).

Step one: find the angle at which the slope is formed, that is;

tan θ= 0.064.

Therefore, θ= inverse of tan, tan^-1(0.064) = 3.7°.

Step two: calculate the net acceleration; this can be calculated using the formula below;

Net acceleration,a= acceleration given in the question,a(1) - (g×sin θ).

Hence, net acceleration,a= 3 - (sin 3.7° × 32).

====> a= 3- 2.1= 0.93 ft/s^2.

Step three: calculate the time taken to cover the distance. This can be calculated by using the formula below;

Top Speed,v= initial velocity, u + (acceleration,a × time taken, t).

The initial velocity is zero, therefore, v=at.

Time taken, t= v/a.

Time taken= 297/0.93.

Time taken, t= 319.355 seconds.

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maxonik [38]

Answer:

  • Grayson had 10 inches of snow in his lawn
  • the snow falls at a constant rate of 0.5 inches per hour
  • no snow was melting
  • the snow has fallen for 3 hours  

Let y be the height of the snow in the lawn

Grayson had 10 inches at the beginning (at t=0) so y= 10

3 hours passed so y= 10 + 3*0.5 = 11.5 inches

Grayson had 11.5 inches after three hours

Assuming that the snow continued to fall for an unkhown time t

y = 0.5*t + 10

we had 10 at the beginning so we add 10 (+10)

the snow is growing by 0.5 inches in the single hour so we multiply by 0.5

t is the time and it can 4, 5, 6 ...... hours

Just like a function :

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2 years ago
-11 2/3 × ( -4 1/5 )=​
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The answer is 49
Solving Steps

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2 years ago
My brother wants to estimate the proportion of Canadians who own their house.What sample size should be obtained if he wants the
AVprozaik [17]

Answer:

a) n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

b) n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}} (a)  

If solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2} (b)  

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.9=0.1 and \alpha/2 =0.05. And the critical value would be given by:  

z_{\alpha/2}=\pm 1.64  

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.02 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07

And rounded up we have that n=1476

Part b

For this case since we don't have a prior estimate we can use \hat p =0.5

n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681

And rounded up we have that n=1681

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Answer:

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Step-by-step explanation:

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