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Vilka [71]
3 years ago
9

Students in a pre-algebra class are given the polynomial 12x2y−6xy+18y2 and told to factor out the greatest common factor. Which

student has made the correct​ choice?(1 point)
Mathematics
1 answer:
serg [7]3 years ago
3 0

This question is not complete

Complete Question

Students in a pre-algebra class are given the polynomial 12x²y - 6xy +18y² and told to factor out the greatest common factor.

Which student has made the correct choice? (1 point)

a) Delia chose 3y because she said that it was a factor of every term.

b) Pedro chose y because he said that the greatest common factor can be found only by looking at the variable terms.

c) Mike chose 6y because he said that it was the largest factor of every term. d) Marisol chose 6 because she said that it was the only greatest common factor in each term.

Answer:

c) Mike chose 6y because he said that it was the largest factor of every term.

Step-by-step explanation:

Step 1

Identify the GCF of the coefficients.

12x²y - 6xy + 18y²

Coefficients are :

12, 6, 18

The Greatest Common Factor for 12, 6, 18 =

The factors of 6 are: 1, 2, 3, 6

The factors of 12 are: 1, 2, 3, 4, 6, 12

The factors of 18 are: 1, 2, 3, 6, 9, 18

Then the greatest common factor is 6.

Step 2

Identify the GCF of the variables.

x²y , xy, y²

The GCF of these variables is y

Step 3

Combine to both GCF's to obtain the GCF of the expression.

= 6 × y

= 6y

The Greatest Common Factor for the expression 12x²y−6xy + 18y² is 6y

Step 4

We factorise

= 12x²y−6xy + 18y²

= 6y(2x² - x + 3y)

Therefore, Option c) Mike chose 6y because he said that it was the largest factor of every term is the correct option.

Mike is correct.

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Try the numbers 22, 23, 24, 25 in the equation 4/3 = 32/d to test whether any of them is a solution. a. 23 is a solution. c. 24
S_A_V [24]

Answer:

c. 24 is a solution

Step-by-step explanation:

Given equation:

\frac{4}{3}=\frac{32}{d}

To test the numbers 22, 23, 24, 25 for the solution.

Solution:

In order to test the given number for the solution, we will plugin each number in the unknown variable d and see if it satisfies the equation.

1) d=22

\frac{4}{3}=\frac{32}{22}

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

\frac{4}{3}=\frac{32\div 2}{22\div 2}

\frac{4}{3}=\frac{16}{11}

The above statement can never be true and hence 22 is not a solution.

2) d=23

\frac{4}{3}=\frac{32}{23}

The fractions can no further be reduced.

The statement can never be true and hence 23 is not a solution.

3) d=24

\frac{4}{3}=\frac{32}{24}

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

\frac{4}{3}=\frac{32\div 8}{24\div 8}

\frac{4}{3}=\frac{4}{3}

The above statement is always true and hence 24 is a solution.

4) d=25

\frac{4}{3}=\frac{32}{25}

The fractions can no further be reduced.

The statement can never be true and hence 25 is not a solution.

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3 years ago
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