Question

Write a polynomial in standard form with the zeros -4,0, 1, and 4.

Answer 1

Answer: $x^4-x^3-16x^2+16x$

Step-by-step explanation:

Factor theorem : If x=a is a zero of a polynomial p(x) then (x-a) is a factor of p(x).

Given: Zeroes of polynomial : -4,0, 1, and 4.

Then Factors = $(x-(-4)), (x-0), (x-1) and (x-4)$   [By factor theorem ]

$=(x+4), (x-0), (x-1) and (x-4)$

Multiplying these factors to get polynomial in standard form.

$(x+4)\times(x-0)\times(x-1)\times(x-4) \\\\= x(x+4)(x-4)(x-1)\\\\= x(x^2-4^2)(x-1)\\\\= x(x^2-16)(x-1)\\\\= x(x^2-16)(x-1)\\\\=x(x^2x+x^2\left(-1\right)+\left(-16\right)x+\left(-16\right)\left(-1\right))\\\\= x(x^3-x^2-16x+16)\\\\=x^4-x^3-16x^2+16x$

Hence, B is the correct option.