Answer:
2.25 + 1.50g > 20
Step-by-step explanation:
hope this help
Answer:
t = (C - 3*A)/B + 3
Step-by-step explanation:
Given in the question that,
the speed with which canoe travelled for first 3 hours = A
the speed with which he travelled for any and all time thereafter = B
As we do not know the values of A, B, or C, so the answer will be an expression for C in terms of A and B.
<h3>Formula to use</h3>
distance = speed x time
C = A*3 + B*(t-3)
Rearranging and solving for t
C - (A*3) = B*(t-3)
C - (A*3) = Bt - B3
C - (A*3) + B3 = Bt
t = C - (A*3) + B3 / B
or
t = (C - 3*A)/B + 3
Answer:
The answer is 306
Step-by-step explanation:
(−18)(−17)
=306
I sent help but no one answered :(
Jk, I got you fam
12(t + 2) + 4 ≥ - 8
12t + 24 + 4 ≥ - 8
12t + 28 ≥ - 8
12t ≥ - 8 - 28
12t ≥ - 36
t ≥ - 36 ÷ 12
t ≥ - 3
Solution:
t ≥ -3
Step-by-step explanation:
The quotient is 0.125
I think this should be the answer
