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3 years ago

Help me with this question plzzzz

Mathematics

1 answer:

zubka84 [21]3 years ago

5 0

V = L * W * H
V = 1/4 * 2/3 * 3/5
V = (1 * 2 * 3) / (4 * 3 * 5)
V = 6/60 reduces to 1/10 m^3 <==

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110$ for 16ft find the unit rate

Neporo4naja [7]

Answer:

6.875 dollars per feet

Step-by-step explanation:

110/16

6.875

8 0

3 years ago

Graph the image of square CDEF after a dilation with a scale factor of 2, centered at the

Likurg_2 [28]

Answer:

Image attached

Step-by-step explanation:

Origin looks to be (0, -1), so move each point out by 2

4 0

3 years ago

Please help me find the slope of the graph thank you a, b, c, d (picture)

alisha [4.7K]

Answer:

D: -75 the balloon is descending at a rate of 75ft per minute

Step-by-step explanation:

To find the slope of any graph, take two points on the graph and subtract them y/x so to get this answer is used the points (0,450) and (2,300) and subtracted the y-values over the x-values

450-300=150

0-2=-2

150/-2 = -75

that is the slope and since it is negative and the slope itself is a diagonal line going towards the x-axis you know it’s descending.

Hope this helps :)

8 0

3 years ago

Read 2 more answers

EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att

aliina [53]

$y=x(x-2)^2$
$\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0$
$\implies x=\dfrac23,x=2$

are the critical points, and judging by the picture alone, you must have $b=\dfrac23$ and $a=2$ . (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

$\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43$

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of $\dfrac{\mathrm dy}{\mathrm dx}=y'$ , which entails first finding the second derivative:

$y'=3x^2-8x+4$
$\implies y''=6x-8$

setting equal to 0 and finding the critical point:

$6x-8=0\implies x=\dfrac86=\dfrac43$

This is to say the minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ *occurs when $x=\dfrac43$ *, but this is not necessarily the same as saying that $\dfrac43$ is the actual minimum value.

The minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ is obtained by evaluating the derivative at this critical point:

$m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43$

4 0

3 years ago

Do all parallelograms have at least one line of symmetry

swat32

I don't think parallelograms have symmetry

6 0

3 years ago