3 years ago

5400÷90=540 tens÷9 tens

Mathematics

1 answer:

solniwko [45]3 years ago

8 0

Hmmm, I'm guessing your asking if that's correct, if so, yes

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Solve the inequality W>Y+H/P for H

Katarina [22]

W > Y + H/P
W - Y > H/P
P(W - Y) > H
H < P(W - Y)

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3 years ago

Need help use screenshot(SAT Prep) In △ABC, AB = BC = 20 and DE ≈ 9.28. Approximate BD. bd equals?

Lilit [14]

Answer:

5.36

Step-by-step explanation:

Given that:

<BAD = <CAE, therefore, BD = EC

Let's take x to be the length of BD = EC

BD + DE + EC = BC

BC = 20,

BD = EC = x

DE ≈ 9.28

Thus,

x + 9.28 + x = 20

x + x + 9.28 = 20

2x + 9.28 = 20

Subtract 9.28 from both sides

2x + 9.28 - 9.28 = 20 - 9.28

2x = 10.72

Divided both sides by 2 to solve for x

$\frac{2x}{2} = \frac{10.72}{2}$

$x = \frac{10.72}{2}$

$x = 5.36$

BD ≈ 5.36

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3 years ago

Find the area of a regular polygon with 8 sides that has a perimeter of 96 inches and an apothem of 5 inches.

Sloan [31]

Answer:

see the attachment photo!

3 0

2 years ago

Jason has read 70% of a 310 page book. How many pages has he read? How many pages has he not read

Luda [366]

Answer:

50%

Step-by-step explanation:

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3 years ago

Read 2 more answers

Express the sum of the polymonial 3x^2+15x-56 and the square of the binomial (x-8) as a polynomial in standard form.

tester [92]

Given:

Polynomial is $3x^2+15x-56$ .

To find:

The sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form.

Solution:

The sum of given polynomial and the square of the binomial (x-8) is

$3x^2+15x-56+(x-8)^2$

$=3x^2+15x-56+x^2-2(x)(8)+8^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

$=3x^2+15x-56+x^2-16x+64$

On combining like terms, we get

$=(3x^2+x^2)+(15x-16x)+(-56+64)$

$=4x^2-x+8$

Therefore, the sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form is $4x^2-x+8$ .

7 0

3 years ago