Answer:
2x^2+4x-16
Step-by-step explanation:
The quadratic can be written as
f(x) = a(x-z1)(x-z2) where z1 and z2 are the roots
f(x) = a (x-2)(x- -4)
a is the leading coefficient
f(x) = 2(x-2)(x+4)
= 2(x^2 -2x+4x-8)
= 2(x^2 +2x-8)
= 2x^2 +4x-16
The correct numbers to use in solving problems about
spans of time like B.C. and A.D. should be “integers”.
Integers are whole numbers (not a fractional number or not a decimal
number) which can take a value of negative, zero, or positive number. Example
of integers would be -1, 0 and 1.
<span>In calculations, the time period would be on the x-axis. Since
B.C. and A.D. are two different spans of time, therefore in the calculations,
the date of BC should be negative (negative x-axis) while the date of AD should
be positive (positive x-axis). This would place the origin as the common
reference.</span>
I need a image otherwise I can't answer this question
Answer:
about 3 seconds
Step-by-step explanation:
hope this helps
