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ohaa [14]
3 years ago
15

We have two fractions,

Mathematics
1 answer:
joja [24]3 years ago
4 0

Answer:

Options (A) and (C).

Step-by-step explanation:

There are two fractions given as

\frac{5}{12},\frac{3}{4}

If we rewrite the fractions by making denominators common we can convert the fraction as,

\frac{5}{12}, \frac{3\times 3}{3\times 4}

Or \frac{5}{12}, \frac{9}{12}

Similarly, both the fractions with common denominators may be\frac{5\times 2}{12\times 2},\frac{3\times 6}{4\times 6}

Or \frac{10}{24},\frac{18}{24}

Therefore, denominators of both the fractions will be 12 and 24.

Options (A) and (C) will be the answer.

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A confectioner bought 15 chocolates for Rs. 1. If he sold all chocolates at 25% profit, how many chocolates were sold for Rs. 1?
shutvik [7]

Answer:

He sold 12 chocolates for 1 Re.

Step-by-step explanation:

He bought 15 chocolates for 1 Rupee

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Sale price = profit + cost price

SP= 25%of 1 + 1 Re

SP = 0.25*1+ 1

SP = 1.25 Rs

He sold 15 chocolates fro 1.25 Rs

Chocolates            Rupees

15                            1.25

x                                1

Applying cross product

x*1.25= 15*1

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2 years ago
Calculate the sum of the infinite series
Rina8888 [55]

Answer:

S_\infty=250.

Step-by-step explanation:

The given infinite series is  50+40+32+\frac{128}{5}+....


The first term of this series is a_1=50.


The common ratio is r=\frac{40}{50}.

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The sum of this infinite series is given by the formula,


S_\infty=\frac{a_1}{1-r}


We now substitute all the above values in to this formula obtain,


S_\infty=\frac{50}{1-\frac{4}{5}}


This implies that,

S_\infty=\frac{50}{\frac{1}{5}}


This simplifies to,


S_\infty=50\times 5


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The correct answer is C.





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