The answer to your question is 22.
Answer:
A)
y^2-6y = 0
or, y(y-6) = 0
or, y = 0 or y = 6
B)
n^2+5n+7 = 7
or, n^2+5n+7-7 = 7-7 ( Subtracting 7 from both sides)
or, n^2+5n = 0
or, n(n+5) = 0
or, n=0 or n= -5
C)
2t^2-14t+3 = 3
or, 2t^2-14t = 0
or, 2t(t-7) = 0
or, t=0 or t=7
D)
1/3x^2+3x-4 = -4
or, 1/3x^2+3x = 0
or, 1/3x(x+9) = 0
or, x=0 or x= -9
E)
Zero is a common solution to each of the equations. This is because each of the equations had a variable outside the parenthesis with an operation of multiplication.
THANK YOU FOR READING.
The second option square root of 2^5
Answer:
1. Josh's father: f Josh: f/2 - 2
2. f + (f/2 - 2) ≥ 49
3. 3/2 f - 2 ≥ 49
3/2 f ≥ 51
3f ≥ 102
f ≥ 34
4. 34
Answer:
-8x+21
Step-by-step explanation:
Use the distributive property.
