The account balance after 3 years if the interest is compounded continuously is $5,142.62
<h3>How to find compound interest?</h3>
- Principal, P = $4,700
- Time,t = 3 years
- Interest rate, r = 3%
r = 3/100
r = 0.03 rate per year,
A = Pe^rt
A = 4,700.00(2.71828)^(0.03)(3)
= 12,775.916^0.09
A = $5,142.62
Therefore, the account balance after 3 years if the interest is compounded continuously is $5,142.62
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Answer:
Where's the graph?
Step-by-step explanation:
The general equation of a line is expressed as y = mx + b where m is the slope of the line and b is the y-intercept. The y-intercept is the value of y when the graph crosses the y- axis. Consequently, it is the value of y when x is zero. The slope is the rate of change of y with respect to the change in x. It is calculated from the ratio of the difference of two y values and the difference of the corresponding x values. Given the points would result to a line, we can determine those elements for the line as follows:
b = 36
m = (y2 - y1) / (x2 - x1)
m = (27 - 36) / (3 -0) = -3
So, the equation of the line would be y = -3x + 36.
(2,-2)(5,7)
7-(-2)= 9
5-2= 3
9/3= 3
slope = 3
(you could also calculate the slope by just counting up how many units it goes up/down when you pick a point from the x-axis and move left/right. basically counting the rise over run)
-0.4 because it is 3.6 - 4
