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zzz [600]
3 years ago
11

If g(x)= square root x-2-3 what is the range of g(x)? A.(0,♾) B. (-1,♾) C. [-2,♾) D. [-3,♾)​

Mathematics
1 answer:
Sladkaya [172]3 years ago
8 0

Answer:

D

Step-by-step explanation:

g(x) = √(x - 2) - 3

The range is all the possible values of g(x).  Since we can't take the square root of a negative number, the lowest that g(x) can be is:

g(x) = √0 - 3

g(x) = -3

The highest that g(x) can be is:

g(x) = √∞ - 3

g(x) = ∞

So the range is:

[-3, ∞)

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