Part 1:
You have the correct answer. You multiply the probability of getting red (6/15) by the probailitiy of getting red (6/15) to get 36/225 which reduces to 4/25
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Part 2:
This is also correct. Nice work. You multiply the probability of getting black (9/15) with the probability of getting red (6/15) to get 54/225 = 6/25
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Part 3:
The probability of picking a black checker is 9/15. If a replacement is made, then the probability of picking another black checker is also 9/15. So,
(9/15)*(9/15) = 81/225 = 9/25
Answer: 9/25
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Part 4:
The probability of rolling a 6 is 1/6. The probability of rolling a 3 is 1/6 as well. This is because there is only one side with this label out of 6 total. Multiply the probabilities
(1/6)*(1/6) = 1/36
Answer: 1/36
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Part 5:
It is impossible to roll a 7 on the six sided cube because the highest number is 6. Therefore the overall probability is 0
Answer: 0
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Part 6:
There are 3 outcomes we want (rolling a 1,2, or 3) out of 6 total. So the probability of rolling a 1,2 or 3 is 3/6 = 1/2. Similarly, the probability of rolling a 4, 5 or 6 is 3/6 = 1/2 as well.
Multiplying the probabilities gives
(1/2)*(1/2) = 1/4
Answer: 1/4
Answer: 2744
Step-by-step explanation: 14x14= 196 x14 =2744
9514 1404 393
Explanation:
Finish the Given statement, make use of the relationships of angles and parallel lines, then finish the algebra.
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2. m∠6 = (1/8)m∠4 . . . . Given
3. m∠6 + m∠4 = 180° . . . . 3. same-side interior angles are supplementary
4. m∠6 + 8·m∠6 = 180° . . . . 4. Substitution (from 2, above: 8·m∠6 = m∠4)
Here is the "algebra" that gets you to line 5:
4a. 9m∠6 = 180° . . . collect terms
4b. m∠6 = 20° . . . . . divide by 9
4c. m∠4 = 8·20° = 160° . . . use the same relation as in step 4
5. m∠6 = 20°, m∠4 = 160° . . . . Algebra
Answer:
The first one and the last one.
Step-by-step explanation:
Explanation:
Because the two pyramids are similar, their corresponding faces are also similar.
So, the hexagonal bases are similar, and the following relationships exist:
perimeter of larger base = k • perimeter of smaller base
area of larger base = k2 • area of smaller base
We know that the height of the larger pyramid is 6 times the height of the smaller pyramid. This implies that the scale factor, k, from the smaller pyramid to the larger pyramid is 6.
So, the perimeter of the larger pyramid’s base is 6 times the perimeter of the smaller pyramid’s base. Also, the area of the larger pyramid’s base is k2 = 62 = 36 times the area of the smaller pyramid’s base.
