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Valentin [98]
3 years ago
14

3. f(x) =(x-1)(x2+2) then f'() :

Mathematics
1 answer:
AlladinOne [14]3 years ago
3 0

Answer:

f'(x)=3x^2-2x+2

Step-by-step explanation:

Assuming that the function is

f(x)=(x-1)(x^2+2)

First, we need to remove the parenthesis. Once this is done, we get

f(x)=x^3-x^2+2x-2

Now that the parenthesis are gone, we can differentiate each term. To do this, we can use the power rule, which states

f(x)=x^n\\f'(x)=nx^{n-1}\\

This gives us

f'(x)=3x^2-2x+2

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Please help!!! I don’t get any of this can someone please explain what to do and how I can get my answer????
diamong [38]
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7 0
2 years ago
How do I solve for Log(x+3)+log2=3 ?
Rzqust [24]

Answer: x = 995

Step-by-step explanation:

In this equation our log doesn't have a base so it is given the default base of 10. This makes our equation really.

log_{10}(x+3) + log_{10}(2) = 3

Now we put every equation as the exponent of our base 10 looks like this:

10^{log_{10} (x+3)}  + 10^{log_{10} (2)} = 10^{3}

Now we cancel out the log base 10 and the 10. We are left with:

(x+3) + (2) = 10^3

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x + 5 = 1000

x = 995

7 0
3 years ago
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